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A digital CMOS IC operating at 10 MHz clock frequency consumes 100 mW power; the same IC operating at 15 MHz clock frequency consumes 140mW power. What is the static power consumption of the IC?
- a)10 mW
- b)15 mW
- c)20 mW
- d)40 mW
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A digital CMOS IC operating at 10 MHz clock frequency consumes 100 mW ...
Static power consumption of a digital CMOS IC is the power consumed by the IC when it is in the static or idle state, i.e., when there is no signal transition happening. It is independent of the clock frequency and is caused by leakage currents and other sources of power dissipation.
Given:
Clock frequency of IC operating at 10 MHz = 10 MHz
Power consumption of IC operating at 10 MHz = 100 mW
Clock frequency of IC operating at 15 MHz = 15 MHz
Power consumption of IC operating at 15 MHz = 140 mW
Let's assume the static power consumption of the IC is Ps.
To find the static power consumption, we need to find the difference in power consumption between the two clock frequencies and subtract the dynamic power consumption caused by the clock frequency difference.
Dynamic power consumption is given by the equation:
Pd = C × V² × f
Where Pd is the dynamic power consumption, C is the total capacitance being charged and discharged per clock cycle, V is the supply voltage, and f is the clock frequency.
Let's assume the total capacitance being charged and discharged per clock cycle is Cd.
For the IC operating at 10 MHz:
Pd1 = Cd × V² × f1 = 100 mW
For the IC operating at 15 MHz:
Pd2 = Cd × V² × f2 = 140 mW
Subtracting the two equations:
Pd2 - Pd1 = Cd × V² × (f2 - f1)
40 mW = Cd × V² × (15 MHz - 10 MHz)
40 mW = Cd × V² × 5 MHz
Now, since static power consumption is independent of the clock frequency, we can assume that the total capacitance being charged and discharged per clock cycle and the supply voltage are the same for both clock frequencies.
Therefore, the static power consumption can be calculated as:
Ps = Pd2 - Pd1 = 40 mW
Hence, the static power consumption of the IC is 20 mW (option C).
Given:
Clock frequency of IC operating at 10 MHz = 10 MHz
Power consumption of IC operating at 10 MHz = 100 mW
Clock frequency of IC operating at 15 MHz = 15 MHz
Power consumption of IC operating at 15 MHz = 140 mW
Let's assume the static power consumption of the IC is Ps.
To find the static power consumption, we need to find the difference in power consumption between the two clock frequencies and subtract the dynamic power consumption caused by the clock frequency difference.
Dynamic power consumption is given by the equation:
Pd = C × V² × f
Where Pd is the dynamic power consumption, C is the total capacitance being charged and discharged per clock cycle, V is the supply voltage, and f is the clock frequency.
Let's assume the total capacitance being charged and discharged per clock cycle is Cd.
For the IC operating at 10 MHz:
Pd1 = Cd × V² × f1 = 100 mW
For the IC operating at 15 MHz:
Pd2 = Cd × V² × f2 = 140 mW
Subtracting the two equations:
Pd2 - Pd1 = Cd × V² × (f2 - f1)
40 mW = Cd × V² × (15 MHz - 10 MHz)
40 mW = Cd × V² × 5 MHz
Now, since static power consumption is independent of the clock frequency, we can assume that the total capacitance being charged and discharged per clock cycle and the supply voltage are the same for both clock frequencies.
Therefore, the static power consumption can be calculated as:
Ps = Pd2 - Pd1 = 40 mW
Hence, the static power consumption of the IC is 20 mW (option C).
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Community Answer
A digital CMOS IC operating at 10 MHz clock frequency consumes 100 mW ...
Concept:
Static power is proportional to the static current, i.e. the current that flows regardless of gate switching.
Dynamic Power is related to the current that flows when switching takes place and is given by for CMOS as:
Static power is proportional to the static current, i.e. the current that flows regardless of gate switching.
Dynamic Power is related to the current that flows when switching takes place and is given by for CMOS as:
P = fCV2cc
Or P = Kf (where K = Vcc2C)
Power consumed by CMOS = Pstatic + Pdynamic
Or P = Kf (where K = Vcc2C)
Power consumed by CMOS = Pstatic + Pdynamic
Calculation:
For f1 = 10MHz, Pconsumed = 100 mW = P1 (Let)
For f2 = 15MHz, Pconsumed = 140 mW = P2
⇒ P1 = Pstatic + Pdynamic
⇒ 100 mW = Pstatic + Kf1
⇒ 100 mW = Pstatic + K(10 M) …1)
Similarly, P2 = 140 mW = Pstatic + K(15 M) …2)
From equation (i) and (ii)
Pstatic = 20 mW
For f1 = 10MHz, Pconsumed = 100 mW = P1 (Let)
For f2 = 15MHz, Pconsumed = 140 mW = P2
⇒ P1 = Pstatic + Pdynamic
⇒ 100 mW = Pstatic + Kf1
⇒ 100 mW = Pstatic + K(10 M) …1)
Similarly, P2 = 140 mW = Pstatic + K(15 M) …2)
From equation (i) and (ii)
Pstatic = 20 mW
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A digital CMOS IC operating at 10 MHz clock frequency consumes 100 mW power; the same IC operating at 15 MHz clock frequency consumes 140mW power. What is the static power consumption of the IC?a)10 mWb)15 mWc)20 mWd)40 mWCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A digital CMOS IC operating at 10 MHz clock frequency consumes 100 mW power; the same IC operating at 15 MHz clock frequency consumes 140mW power. What is the static power consumption of the IC?a)10 mWb)15 mWc)20 mWd)40 mWCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A digital CMOS IC operating at 10 MHz clock frequency consumes 100 mW power; the same IC operating at 15 MHz clock frequency consumes 140mW power. What is the static power consumption of the IC?a)10 mWb)15 mWc)20 mWd)40 mWCorrect answer is option 'C'. Can you explain this answer?.
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