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A system with the polynomial s4 + 5s3 + 3s2 + 6s + 5 = 0 is:
  • a)
    Unstable
  • b)
    Marginally stable
  • c)
    In equilibrium
  • d)
    Stable
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A system with the polynomials4 + 5s3 + 3s2 + 6s + 5 = 0 is:a)Unstableb...
Explanation:

  • The given polynomial is 4s^3 + 5s^2 + 3s + 5 = 0

  • To determine the stability of the system, we need to analyze the roots of the polynomial.

  • For a polynomial of degree n, there can be n roots.

  • If all the roots have negative real parts, then the system is stable.

  • If all the roots have positive real parts, then the system is unstable.

  • If some roots have positive real parts and some have negative real parts, then the system is marginally stable.



Analysis of the given polynomial:

  • The polynomial has 3 complex roots and no real roots.

  • Complex roots always come in complex conjugate pairs.

  • Therefore, the polynomial has 1 real root and 2 complex conjugate roots.

  • The real root can be positive or negative, but the complex roots always have negative real parts.

  • Therefore, the system is unstable as it has at least one root with a positive real part.



Conclusion:

  • The system with the polynomial 4s^3 + 5s^2 + 3s + 5 = 0 is unstable.

Free Test
Community Answer
A system with the polynomials4 + 5s3 + 3s2 + 6s + 5 = 0 is:a)Unstableb...
The given characteristic equation is: s4 + 5s3 + 3s2 + 6s + 5 = 0. We first need to find the roots by creating the Routh's array table.
Routh's array table is shown below:

In the first column of the above table, we have two sign changes. It means that two roots are in the RHS plane. Hence, the system is unstable.
Hence the correct answer is an option (a).
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A system with the polynomials4 + 5s3 + 3s2 + 6s + 5 = 0 is:a)Unstableb)Marginally stablec)In equilibriumd)StableCorrect answer is option 'A'. Can you explain this answer?
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