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A 3 bit comparator circuit gives logic 1 output whenever the 3 bit input A is greater than the 3 bit input B. The output Boolean function y is represented by a K-map. The no. of 1 in the K-map is –
  • a)
    56
  • b)
    28
  • c)
    32
  • d)
    24
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A 3 bit comparator circuit gives logic 1 output whenever the 3 bit inp...
Total no. of input combination of A & B are = 23 x 23 = 64
In 64 combination only in 8 combination A = B situation occurs. So the no. of combination for which A ≠ B is 64 - 8 = 56
Only of these 56 combinations only in 28 combinations A > B situation occur.
So, the no of 1 in K map will be 28
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Community Answer
A 3 bit comparator circuit gives logic 1 output whenever the 3 bit inp...
The number of 1's in the K-map depends on the values of inputs A and B. Without specific values for A and B, it is not possible to determine the number of 1's in the K-map.
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A 3 bit comparator circuit gives logic 1 output whenever the 3 bit input A is greater than the 3 bit input B. The output Boolean function y is represented by a K-map. The no. of 1 in the K-map is –a)56b)28c)32d)24Correct answer is option 'B'. Can you explain this answer?
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