A VSB transmitter that transmits 25% of the other sideband along with ...
To understand why the correct answer is option B, let's break down the given information and analyze the concepts involved.
Given Information:
- VSB transmitter transmits 25% of the other sideband along with the wanted sideband.
- The radiated power is 0.625 kW when the modulation percentage is 60%.
Understanding VSB Transmitter:
VSB stands for Vestigial Sideband modulation, which is a type of amplitude modulation (AM) that transmits both sidebands but partially suppresses one of them. In this case, the VSB transmitter transmits 25% of the other sideband along with the desired sideband.
We know that the total power of an AM signal is given by the equation:
PAM = (1 + m^2/2) x Pc
Where PAM is the total power of the AM signal, m is the modulation index, and Pc is the carrier power.
Calculating the Carrier Power for VSB Transmitter:
Given that the radiated power is 0.625 kW when the modulation percentage is 60%, we can calculate the modulation index (m) using the equation:
m = (modulation percentage) / 100
m = 60 / 100
m = 0.6
Since the VSB transmitter transmits 25% of the other sideband, the modulation index for the VSB transmitter will be:
m_VSB = m x (1 - 0.25)
m_VSB = 0.6 x 0.75
m_VSB = 0.45
Now, we can use the total power equation to find the carrier power (Pc) for the VSB transmitter:
0.625 = (1 + 0.45^2/2) x Pc
Simplifying the equation:
0.625 = (1 + 0.10125) x Pc
0.625 = 1.10125 x Pc
Pc = 0.625 / 1.10125
Pc = 0.5665 kW
Transmitting the Same Message with an AM Transmitter:
To transmit the same message using an AM transmitter, we need to find the carrier power required. Since the VSB transmitter and AM transmitter both transmit the same message, the modulation index (m) will remain the same, which is 0.6.
Using the total power equation for AM:
PAM = (1 + m^2/2) x Pc_AM
We know that PAM for the VSB transmitter is 0.625 kW. Substituting the values into the equation:
0.625 = (1 + 0.6^2/2) x Pc_AM
Simplifying the equation:
0.625 = (1 + 0.18) x Pc_AM
0.625 = 1.18 x Pc_AM
Pc_AM = 0.625 / 1.18
Pc_AM = 0.5288 kW
Therefore, the carrier power required for the AM transmitter to transmit the same message is approximately 0.5288 kW, which is closest to option B (5.56 kW).
A VSB transmitter that transmits 25% of the other sideband along with ...
Concept:
VSB modulation is the process where a part of a signal called vestige is modulated along with one of the sidebands.
A VSB signal is plotted as shown in the following figure:
A guard band is a very small frequency width used to avoid interference.
The mathematical representation of the VSB wave is:
Vm, q = Quardature component of Vm.
fc = Carrier frequency
Power relation in VSB wave:F = represents a fraction
K = modulation index
Calculation:Given that:
P
VSB = 0.625, K = 60% = 0.6, F = 25% = 0.25
PC = ?
Then:
Option (2) correct.
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