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)A barrel contains a mixture of wine and water in the ratio 3:1. How much fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1:1?
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)A barrel contains a mixture of wine and water in the ratio 3:1. How m...
Solution:

Given: A barrel contains a mixture of wine and water in the ratio 3:1.

To find: How much fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1:1.

Let's assume that the barrel initially contains 4 liters of mixture (3 liters of wine and 1 liter of water).

Let x be the fraction of the mixture that must be drawn off and substituted by water.

Step 1: Drawing off the fraction of the mixture.

The fraction of the mixture that must be drawn off is x/4.

After drawing off x/4 fraction of the mixture, the barrel contains (4 - x/4) liters of the mixture.

Step 2: Substituting the drawn-off fraction with water.

The fraction of water that must be added is also x/4.

After substituting the drawn-off fraction with water, the barrel contains (1/4 * x + 1) liters of water.

Step 3: Calculating the ratio of wine and water in the resultant mixture.

The quantity of wine in the new mixture is the same as it was initially, i.e., 3 liters.

The quantity of water in the new mixture is (1/4 * x + 1) liters.

The ratio of wine and water in the new mixture is:

3/(1/4 * x + 1) = 1/1

Solving this equation, we get:

x = 3/4

Therefore, 3/4 fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1:1.
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)A barrel contains a mixture of wine and water in the ratio 3:1. How much fraction of the mixture must be drawn off and substituted by water so that the ratio of wine and water in the resultant mixture in the barrel becomes 1:1?
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