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Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)
- a)1100
- b)0011
- c)0000
- d)1111
Correct answer is option 'C'. Can you explain this answer?
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Assume that a 4-bit serial in/serial out shift register is initially c...
Explanation:
To understand the output pattern after the second clock pulse, we need to analyze the behavior of a 4-bit serial in/serial out shift register.
Serial In/Serial Out Shift Register:
A serial in/serial out shift register is a type of shift register where data is shifted in and shifted out serially, one bit at a time. In this type of shift register, the data is shifted in from the serial input and shifted out from the serial output.
Initial State:
The shift register is initially clear, which means all the bits in the register are set to 0.
Storing the Nibble 1100:
To store the nibble 1100 in the shift register, we need to input the bits serially, starting from the right-most bit.
1. Clock Pulse 1:
- The right-most bit of the nibble, which is 0, is inputted into the shift register.
- Since the shift register is initially clear, all the bits in the register remain 0.
- The output pattern after the first clock pulse is 0000.
2. Clock Pulse 2:
- The second right-most bit of the nibble, which is 0, is inputted into the shift register.
- The bits in the shift register are shifted to the right by one position.
- The right-most bit is shifted out from the serial output.
- The output pattern after the second clock pulse is 0000.
Output Pattern:
After the second clock pulse, the output pattern is 0000.
Therefore, the correct answer is option C) 0000.
To understand the output pattern after the second clock pulse, we need to analyze the behavior of a 4-bit serial in/serial out shift register.
Serial In/Serial Out Shift Register:
A serial in/serial out shift register is a type of shift register where data is shifted in and shifted out serially, one bit at a time. In this type of shift register, the data is shifted in from the serial input and shifted out from the serial output.
Initial State:
The shift register is initially clear, which means all the bits in the register are set to 0.
Storing the Nibble 1100:
To store the nibble 1100 in the shift register, we need to input the bits serially, starting from the right-most bit.
1. Clock Pulse 1:
- The right-most bit of the nibble, which is 0, is inputted into the shift register.
- Since the shift register is initially clear, all the bits in the register remain 0.
- The output pattern after the first clock pulse is 0000.
2. Clock Pulse 2:
- The second right-most bit of the nibble, which is 0, is inputted into the shift register.
- The bits in the shift register are shifted to the right by one position.
- The right-most bit is shifted out from the serial output.
- The output pattern after the second clock pulse is 0000.
Output Pattern:
After the second clock pulse, the output pattern is 0000.
Therefore, the correct answer is option C) 0000.
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Community Answer
Assume that a 4-bit serial in/serial out shift register is initially c...
In Serial-In/Serial-Out shift register, data will be shifted one at a time with every clock pulse. Therefore,
Wait | Store
1100 | 0000
110 | 0000 1st clock
11 | 0000 2nd clock.
Wait | Store
1100 | 0000
110 | 0000 1st clock
11 | 0000 2nd clock.
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Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)a)1100b)0011c)0000d)1111Correct answer is option 'C'. Can you explain this answer?
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