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An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, then
- a)R = 10 ns, S = 80 ns
- b)R = 40 ns, S = 10 ns
- c)R = 10 ns, S = 10 ns
- d)R = 80 ns, S = 10 ns
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
An 8-bit ripple counter and an 8 bit synchronous counter are made usin...
Explanation:
To understand why option D is the correct answer, let's first understand the concept of ripple counters and synchronous counters.
Ripple Counter:
- A ripple counter is an asynchronous counter where the output of one flip flop serves as the clock input for the next flip flop in the chain.
- The output of each flip flop changes state on the rising edge of the clock signal.
- Therefore, the propagation delay of each flip flop adds up, resulting in a cumulative delay in the ripple counter.
Synchronous Counter:
- A synchronous counter is a counter where all flip flops are driven by the same clock signal.
- The clock signal is applied simultaneously to all flip flops, and the output of each flip flop changes state on the rising edge of the clock signal.
- Therefore, all flip flops in a synchronous counter change state simultaneously, resulting in no cumulative delay.
Now, let's analyze the given information:
- Both the ripple counter and the synchronous counter are 8-bit counters, meaning they have 8 flip flops.
- The propagation delay of each flip flop is given as 10 ns.
Propagation Delay in the Ripple Counter:
- Since the ripple counter is an asynchronous counter, the propagation delay of each flip flop adds up.
- In an 8-bit ripple counter, there are 8 flip flops, so the worst-case delay would be 8 times the propagation delay of each flip flop.
- Therefore, the worst-case delay in the ripple counter (R) would be 8 * 10 ns = 80 ns.
Propagation Delay in the Synchronous Counter:
- In a synchronous counter, all flip flops change state simultaneously on the rising edge of the clock signal.
- Therefore, there is no cumulative delay in a synchronous counter.
- The worst-case delay in the synchronous counter (S) would be the propagation delay of a single flip flop, which is given as 10 ns.
Hence, the correct answer is option D: R = 80 ns (worst-case delay in the ripple counter) and S = 10 ns (worst-case delay in the synchronous counter).
To understand why option D is the correct answer, let's first understand the concept of ripple counters and synchronous counters.
Ripple Counter:
- A ripple counter is an asynchronous counter where the output of one flip flop serves as the clock input for the next flip flop in the chain.
- The output of each flip flop changes state on the rising edge of the clock signal.
- Therefore, the propagation delay of each flip flop adds up, resulting in a cumulative delay in the ripple counter.
Synchronous Counter:
- A synchronous counter is a counter where all flip flops are driven by the same clock signal.
- The clock signal is applied simultaneously to all flip flops, and the output of each flip flop changes state on the rising edge of the clock signal.
- Therefore, all flip flops in a synchronous counter change state simultaneously, resulting in no cumulative delay.
Now, let's analyze the given information:
- Both the ripple counter and the synchronous counter are 8-bit counters, meaning they have 8 flip flops.
- The propagation delay of each flip flop is given as 10 ns.
Propagation Delay in the Ripple Counter:
- Since the ripple counter is an asynchronous counter, the propagation delay of each flip flop adds up.
- In an 8-bit ripple counter, there are 8 flip flops, so the worst-case delay would be 8 times the propagation delay of each flip flop.
- Therefore, the worst-case delay in the ripple counter (R) would be 8 * 10 ns = 80 ns.
Propagation Delay in the Synchronous Counter:
- In a synchronous counter, all flip flops change state simultaneously on the rising edge of the clock signal.
- Therefore, there is no cumulative delay in a synchronous counter.
- The worst-case delay in the synchronous counter (S) would be the propagation delay of a single flip flop, which is given as 10 ns.
Hence, the correct answer is option D: R = 80 ns (worst-case delay in the ripple counter) and S = 10 ns (worst-case delay in the synchronous counter).
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Community Answer
An 8-bit ripple counter and an 8 bit synchronous counter are made usin...
Concept:
For an n-bit ripple counter, the MSB is generated only when the carry form all the pervious flip-flip are propagated to the MSB flip flop.
So, the maximum time(Worst-Case delay) taken for the output of the Ripple counter to be stable = n × td (where td is the propagation delay of each flip flop)
But in an n-bit synchronous counter, the time taken for the output to be stable is simply the propagation delay of 1 flip-flop i.e. td
Calculation:
Given n = 8 bit and td = 10 ns.
For Ripple counter, the worst-case delay = n × tb = 8 × 10 ns = 80 nsec.
For Synchronous-Counter the worst-case delay is td only, which is 10 ns.
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An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer?
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An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer?.
An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An 8-bit ripple counter and an 8 bit synchronous counter are made using flip flops having a propagation delay of 10 ns each. If the worst-case delay in the ripple counter and the synchronous counter be R and S respectively, thena)R = 10 ns, S = 80 nsb)R = 40 ns, S = 10 nsc)R = 10 ns, S = 10 nsd)R = 80 ns, S = 10 nsCorrect answer is option 'D'. Can you explain this answer?.
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