All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  A bar magnet (pole strength=m, magnetic momen... Start Learning for Free
SaveJoin the Discussion on the App
A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that?
Clear all your JEE doubts with EduRev
Verified Answer
A bar magnet (pole strength=m, magnetic moment =M) is divided into fou...
If a bar magnet is divided into four equal parts by cutting along the axial direction, the pole strength and magnetic moment of each part would be reduced by a factor of 4. This is because the pole strength and magnetic moment of a magnet are proportional to the mass and volume of the magnet, respectively. When the magnet is divided into four equal parts, the mass and volume of each part are reduced by a factor of 4, leading to a corresponding reduction in the pole strength and magnetic moment.
Therefore, if the original magnet has a pole strength of m and a magnetic moment of M, each of the four parts would have a pole strength of m/4 and a magnetic moment of M/4.

This question is part of UPSC exam. View all JEE courses
Most Upvoted Answer
A bar magnet (pole strength=m, magnetic moment =M) is divided into fou...
Introduction:

A bar magnet is a magnetized material with two opposite poles, known as the north and south poles. The pole strength of a magnet is a measure of the strength of the magnetic field produced by each pole. The magnetic moment of a magnet is the product of its pole strength and the distance between its poles. In this scenario, we have a bar magnet with pole strength 'm' and magnetic moment 'M', which is divided into four equal parts by cutting along its axial direction. Let's analyze the magnetic moments of the divided parts.

Dividing the Bar Magnet:

When the bar magnet is divided into four equal parts along its axial direction, each part will have an equal length and width. This division will result in four smaller magnets, each with its own pole strength and magnetic moment.

Magnetic Moment of Each Part:

The magnetic moment of a magnet is the product of its pole strength and the distance between its poles. As the bar magnet is divided into four equal parts, the distance between the poles of each part remains the same. However, the pole strength of each part may vary.

Pole Strength of Each Part:

Since the bar magnet is divided into four equal parts, the pole strength of each part will also be one-fourth of the original pole strength 'm'. Therefore, the pole strength of each part will be m/4.

Magnetic Moment of Each Part:

The magnetic moment of each part can be calculated by multiplying the pole strength of the part with the distance between its poles. As the distance remains the same for all the parts, the magnetic moment of each part will also be one-fourth of the original magnetic moment 'M'. Therefore, the magnetic moment of each part will be M/4.

Summary:

In summary, when a bar magnet with pole strength 'm' and magnetic moment 'M' is divided into four equal parts along its axial direction, each part will have a pole strength of m/4 and a magnetic moment of M/4. The division does not affect the distance between the poles, but it redistributes the pole strength among the smaller magnets.
Explore Courses for JEE exam

Similar JEE Doubts

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

Top Courses for JEEView all

Top Courses for JEE

A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that?
Question Description
A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that?.
Solutions for A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? defined & explained in the simplest way possible. Besides giving the explanation of A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that?, a detailed solution for A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? has been provided alongside types of A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? theory, EduRev gives you an ample number of questions to practice A bar magnet (pole strength=m, magnetic moment =M) is divided into four equal parts by cutting along axial magnetic moment of each part is m' and M' such that? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup