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The ratio of the price of two flats was 4:5 3 years later when the price of first increase by 10% and that the second by rupees 6000 the ratio of their prices become 11 : 15 find the original price of two?
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The ratio of the price of two flats was 4:5 3 years later when the pri...
Problem: The ratio of the price of two flats was 4:5. 3 years later when the price of first increased by 10% and that of the second by Rs. 6000, the ratio of their prices became 11:15. Find the original price of two flats.

Solution:

Let the original prices of two flats be 4x and 5x.

Step 1: Finding the new prices of two flats after 3 years.

The price of the first flat increased by 10%, so its new price after 3 years will be:

4x + 10% of 4x = 4x + 0.4x = 4.4x

The price of the second flat increased by Rs. 6000, so its new price after 3 years will be:

5x + 6000 = 5x + 6000

Step 2: Forming an equation using the given information.

According to the question, the ratio of the new prices of the two flats is 11:15. So, we can write:

4.4x : (5x + 6000) = 11 : 15

Step 3: Solving the equation.

Cross-multiplying, we get:

4.4x x 15 = 11 x (5x + 6000)

Simplifying, we get:

66x = 55x + 66000

11x = 66000

x = 6000

Step 4: Finding the original prices of two flats.

The original price of the first flat = 4x = 4 x 6000 = Rs. 24000

The original price of the second flat = 5x = 5 x 6000 = Rs. 30000

Therefore, the original prices of the two flats were Rs. 24000 and Rs. 30000.

Conclusion:

The original prices of two flats were Rs. 24000 and Rs. 30000.
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The ratio of the price of two flats was 4:5 3 years later when the price of first increase by 10% and that the second by rupees 6000 the ratio of their prices become 11 : 15 find the original price of two?
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