Probability of getting 7 or 11 in a throw of 2 dice:

To find the probability of getting a sum of 7 or 11 in a throw of 2 dice, we need to determine the number of favorable outcomes and the total number of possible outcomes.

Favorable outcomes:
There are 6 ways to get a sum of 7 with two dice: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1).
There are 2 ways to get a sum of 11 with two dice: (5, 6), (6, 5).
Therefore, the total number of favorable outcomes is 6 + 2 = 8.

Total number of possible outcomes:
When two dice are thrown, each die can take on 6 possible outcomes (numbers 1 to 6). Since there are two dice, the total number of possible outcomes is 6 * 6 = 36.

Probability:
The probability of an event is defined as the number of favorable outcomes divided by the total number of possible outcomes.
In this case, the probability of getting a sum of 7 or 11 is 8/36.

Simplifying the fraction by dividing both the numerator and denominator by 4, we get 2/9.

Therefore, the chance of getting 7 or 11 in a throw of 2 dice is 2/9.

Summary:
- The probability of getting a sum of 7 or 11 in a throw of 2 dice is 2/9.
- The number of favorable outcomes is 8 (6 ways to get a sum of 7 and 2 ways to get a sum of 11).
- The total number of possible outcomes is 36 (6 possible outcomes for each die).
- The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.