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Sum of all natural number between 500 and 1000 divisble by 13?
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Sum of all natural number between 500 and 1000 divisble by 13?
Sum of Natural Numbers Divisible by 13 between 500 and 1000


Step 1: Find the first number divisible by 13 between 500 and 1000

The first number divisible by 13 between 500 and 1000 is 507. This is found by dividing 500 by 13 and taking the next highest integer, then multiplying by 13.


Step 2: Find the last number divisible by 13 between 500 and 1000

The last number divisible by 13 between 500 and 1000 is 988. This is found by dividing 1000 by 13 and taking the nearest lower integer, then multiplying by 13.


Step 3: Find the number of terms

The number of terms in this sequence can be found by dividing the difference between the first and last number by 13 and adding 1. In this case, there are 38 terms.


Step 4: Use the formula for the sum of an arithmetic sequence

The formula for the sum of an arithmetic sequence is:

Sum = n/2 x (first term + last term)

where n is the number of terms


Step 5: Substitute the values and calculate

Substituting the values, we get:

Sum = 38/2 x (507 + 988) = 19 x 1495 = 28,405


Step 6: Write the final answer

The sum of all natural numbers between 500 and 1000 that are divisible by 13 is 28,405.
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Sum of all natural number between 500 and 1000 divisble by 13?
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