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A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is?
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A box contains rs 56 in the form of coins of rupees,50 paise and 25 pa...
Given information:
- The box contains Rs 56 in the form of coins of rupees, 50 paise, and 25 paise.
- The number of 50 paise coins is double the number of 25 paise coins.
- The number of 50 paise coins is four times the number of one rupee coins.
Let's assume:
- Let the number of one rupee coins be x.
- Let the number of 50 paise coins be 2y (twice the number of 25 paise coins).
- Let the number of 25 paise coins be y.
Calculating the total amount in terms of coins:
- The value of x one rupee coins is Rs x.
- The value of 2y fifty paise coins is Rs 2y * 50 paise = Rs y.
- The value of y twenty-five paise coins is Rs y * 25 paise = Rs y / 2.
Given total amount:
- The total amount in the box is Rs 56.
Equation:
- Rs x + Rs y + Rs y / 2 = Rs 56
Simplifying the equation:
- Multiplying through by 2 to eliminate the fraction: 2 * Rs x + 2 * Rs y + Rs y = 2 * Rs 56
- Simplifying: Rs 2x + Rs 2y + Rs y = Rs 112
- Combining like terms: Rs 2x + Rs 3y = Rs 112
Finding the possible values of x and y:
- Since the number of coins cannot be negative, x and y should be positive integers.
- We can try different values of x and find the corresponding value of y that satisfies the equation.
Let's try some values:
- Let x = 1, then 2 + 3y = 112 => 3y = 110 => y = 110 / 3 (not an integer)
- Let x = 2, then 4 + 3y = 112 => 3y = 108 => y = 108 / 3 = 36
- Let x = 3, then 6 + 3y = 112 => 3y = 106 => y = 106 / 3 (not an integer)
- Let x = 4, then 8 + 3y = 112 => 3y = 104 => y = 104 / 3 (not an integer)
Therefore:
- The only value of x that gives a positive integer value for y is x = 2.
- So, the number of one rupee coins is x = 2.
- The number of 25 paise coins is y = 36.
- The number of 50 paise coins is 2y = 2 * 36 = 72.
- The box contains Rs 56 in the form of coins of rupees, 50 paise, and 25 paise.
- The number of 50 paise coins is double the number of 25 paise coins.
- The number of 50 paise coins is four times the number of one rupee coins.
Let's assume:
- Let the number of one rupee coins be x.
- Let the number of 50 paise coins be 2y (twice the number of 25 paise coins).
- Let the number of 25 paise coins be y.
Calculating the total amount in terms of coins:
- The value of x one rupee coins is Rs x.
- The value of 2y fifty paise coins is Rs 2y * 50 paise = Rs y.
- The value of y twenty-five paise coins is Rs y * 25 paise = Rs y / 2.
Given total amount:
- The total amount in the box is Rs 56.
Equation:
- Rs x + Rs y + Rs y / 2 = Rs 56
Simplifying the equation:
- Multiplying through by 2 to eliminate the fraction: 2 * Rs x + 2 * Rs y + Rs y = 2 * Rs 56
- Simplifying: Rs 2x + Rs 2y + Rs y = Rs 112
- Combining like terms: Rs 2x + Rs 3y = Rs 112
Finding the possible values of x and y:
- Since the number of coins cannot be negative, x and y should be positive integers.
- We can try different values of x and find the corresponding value of y that satisfies the equation.
Let's try some values:
- Let x = 1, then 2 + 3y = 112 => 3y = 110 => y = 110 / 3 (not an integer)
- Let x = 2, then 4 + 3y = 112 => 3y = 108 => y = 108 / 3 = 36
- Let x = 3, then 6 + 3y = 112 => 3y = 106 => y = 106 / 3 (not an integer)
- Let x = 4, then 8 + 3y = 112 => 3y = 104 => y = 104 / 3 (not an integer)
Therefore:
- The only value of x that gives a positive integer value for y is x = 2.
- So, the number of one rupee coins is x = 2.
- The number of 25 paise coins is y = 36.
- The number of 50 paise coins is 2y = 2 * 36 = 72.
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A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is?
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A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is?.
A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains rs 56 in the form of coins of rupees,50 paise and 25 paise. The number of 50 paise coin is double the number of 25 Paise coins and four times of one rupee coins. The numbers of 50 paise coins in the box is?.
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