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There are 24 points on a plane such that 10 of them are collinear. No 4 points are vertices of a cyclic quadrilateral. Find the maximum number of circles that can be drawn through any three points.
Correct answer is '1904'. Can you explain this answer?
Most Upvoted Answer
There are 24 points on a plane such that 10 of them are collinear. No...
A circle can be drawn through any three points on a given plane, provided they are not collinear.
Now, there are 24 points, so the total number of ways three points can be chosen = 24C3
​However, if we choose any three of the given ten points that are collinear, we won't be able to form a circle.
Hence, those cases need to be excluded.
Total number of ways = 10C3
The total number of circles = 24C3 - 10C3
= 1904
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There are 24 points on a plane such that 10 of them are collinear. No...
Problem Statement:
There are 24 points on a plane such that 10 of them are collinear. No 4 points are vertices of a cyclic quadrilateral. Find the maximum number of circles that can be drawn through any three points.

Solution:

Understanding the Constraints:
To find the maximum number of circles that can be drawn through any three points, we need to consider the given constraints:
- There are 24 points on a plane.
- 10 of these points are collinear.
- No 4 points are vertices of a cyclic quadrilateral.

Analysis:
To find the maximum number of circles, we need to maximize the number of unique triplets of points that can form a circle. Let's consider the possible scenarios:

Scenario 1: No collinear points
In this scenario, all 24 points are non-collinear. To form a circle, we need 3 non-collinear points. Hence, the maximum number of circles in this scenario is C(24, 3) = 24! / (3! * (24 - 3)!) = 2024.

Scenario 2: Maximum collinear points
In this scenario, we assume that all 10 collinear points are part of every circle. To form a circle, we need 3 points. We can choose 3 points from the collinear set in C(10, 3) ways. For the remaining 14 non-collinear points, we can choose 3 points in C(14, 3) ways. Hence, the maximum number of circles in this scenario is C(10, 3) * C(14, 3) = 700 * 364 = 254800.

Scenario 3: Combination of collinear and non-collinear points
In this scenario, we consider a combination of collinear and non-collinear points. Let's assume we have 'a' collinear points and 'b' non-collinear points. To form a circle, we need 3 points. We can choose 3 points from the collinear set in C(a, 3) ways. For the remaining non-collinear points, we can choose 3 points in C(b, 3) ways. Hence, the maximum number of circles in this scenario is C(a, 3) * C(b, 3).

Optimization:
To maximize the number of circles, we need to find the scenario that yields the highest number of circles. Comparing the number of circles in each scenario, we find that Scenario 2 yields the maximum number of circles (254800).

Final Answer:
Hence, the maximum number of circles that can be drawn through any three points is 254800.
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There are 24 points on a plane such that 10 of them are collinear. No 4 points are vertices of a cyclic quadrilateral. Find the maximum number of circles that can be drawn through any three points.Correct answer is '1904'. Can you explain this answer?
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