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A three phase star-connected load is drawing power at a voltage of 0.9 pu and 0.8 power factor lagging. The three phase base power and base current are 100 MVA and 437.38 A respectively. The line-to-line load voltage in kV is _______.    (Important - Enter only the numerical value in the answer)
    Correct answer is between '117,120'. Can you explain this answer?
    Verified Answer
    A three phase star-connected load is drawing power at a voltage of 0.9...
    V = 0.9 pu. and cos ϕ = 0.8 lag.
    Base power = 100 MVA
    Base current = 437.38 A
    P.U. value = Actual value / base value
    Now, the base

     
    Now, Vactual = 0.9 pu × 132 kV
    ⇒ Vactual = 118.8 kV
    ⇒ VL−L = Vactual
    VL-L = 118.80 kV
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    Most Upvoted Answer
    A three phase star-connected load is drawing power at a voltage of 0.9...
    Given data:
    - Three-phase star-connected load
    - Voltage: 0.9 pu
    - Power factor: 0.8 lagging
    - Base power: 100 MVA
    - Base current: 437.38 A

    To determine the line-to-line load voltage in kV, we need to follow the steps below:

    1. Calculate the apparent power (S) drawn by the load:
    - The apparent power is given by the formula S = √3 * V * I, where V is the line voltage and I is the line current.
    - As the load is star-connected, the line current (I) is equal to the phase current (Iph).
    - Therefore, S = √3 * V * Iph.

    2. Calculate the real power (P) drawn by the load:
    - The real power is given by the formula P = S * power factor.
    - Therefore, P = √3 * V * Iph * power factor.

    3. Calculate the line voltage (V) in kV:
    - The line voltage (V) can be calculated using the formula V = Vpu * Vbase, where Vpu is the voltage in per unit and Vbase is the base voltage.
    - Given: Vpu = 0.9 and Vbase = 100 MVA.
    - Therefore, V = 0.9 * 100 MVA = 90 MVA.

    4. Convert the line voltage to kV:
    - 1 MVA = 1000 kVA.
    - Therefore, the line voltage in kV = 90 MVA * 1000 = 90000 kVA = 90 kV.

    Therefore, the line-to-line load voltage is 90 kV.
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    Community Answer
    A three phase star-connected load is drawing power at a voltage of 0.9...
    V = 0.9 pu. and cos ϕ = 0.8 lag.
    Base power = 100 MVA
    Base current = 437.38 A
    P.U. value = Actual value / base value
    Now, the base

     
    Now, Vactual = 0.9 pu × 132 kV
    ⇒ Vactual = 118.8 kV
    ⇒ VL−L = Vactual
    VL-L = 118.80 kV
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    Question Description
    A three phase star-connected load is drawing power at a voltage of 0.9 pu and 0.8 power factor lagging. The three phase base power and base current are 100 MVA and 437.38 A respectively. The line-to-line load voltage in kV is _______. (Important - Enter only the numerical value in the answer)Correct answer is between '117,120'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A three phase star-connected load is drawing power at a voltage of 0.9 pu and 0.8 power factor lagging. The three phase base power and base current are 100 MVA and 437.38 A respectively. The line-to-line load voltage in kV is _______. (Important - Enter only the numerical value in the answer)Correct answer is between '117,120'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A three phase star-connected load is drawing power at a voltage of 0.9 pu and 0.8 power factor lagging. The three phase base power and base current are 100 MVA and 437.38 A respectively. The line-to-line load voltage in kV is _______. (Important - Enter only the numerical value in the answer)Correct answer is between '117,120'. Can you explain this answer?.
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