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What is the radius of a metal atom if it crystallizes with body-centered lattice having a unit cell edge of 333 Pico meter?
  • a)
    1538.06 pm
  • b)
    769.03 pm
  • c)
    288.38 pm
  • d)
    144.19 pm
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the radius of a metal atom if it crystallizes with body-center...
For body-centered unit cells, the relation between radius of a particle ‘r’ and edge length of unit cell ‘a’ is given as 
On substituting the values we get r =  x 333 pm = 144.19 pm is the radius of the metal atom.
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Most Upvoted Answer
What is the radius of a metal atom if it crystallizes with body-center...
For body-centered unit cells, the relation between radius of a particle ‘r’ and edge length of unit cell ‘a’ is given as 
On substituting the values we get r =  x 333 pm = 144.19 pm is the radius of the metal atom.
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Community Answer
What is the radius of a metal atom if it crystallizes with body-center...
Given Data:
Unit cell edge = 333 pm

Formula:
In a body-centered cubic lattice, the radius of the atom (r) can be calculated using the formula:
r = √3/4 * a

Calculation:
Given that the unit cell edge (a) = 333 pm
Substitute the value of a in the formula:
r = √3/4 * 333 pm
r = 144.19 pm
Therefore, the radius of the metal atom is 144.19 pm, which corresponds to option 'D'.
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What is the radius of a metal atom if it crystallizes with body-centered lattice having a unit cell edge of 333 Pico meter?a)1538.06 pmb)769.03 pmc)288.38 pmd)144.19 pmCorrect answer is option 'D'. Can you explain this answer?
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