Chemistry Exam > Chemistry Questions > Rubidium Chloride (RbCl) has NaCl like struct...
Start Learning for Free
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 Å, what is the unit cell edge length for RbCl? (Assuming anion-anion contact)
- a)4.25 Å
- b)4.78 Å
- c)4.32 Å
- d)5.14 Å
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. ...
Given,
Radius of Chloride ion (r–) = 0.154 nm
Distance between the centres of the Chloride ions = 2 x 0.154 = 0.308 nm
Let the edge length of cube = a
Distance between Rb+ and Cl– ions = a/2
Therefore, the distance between Cl– ions = (2 x (a/2)2)1/2
0.308 = (2 x (a/2)2)1/2
0.094864 = 2 x (a/2)2
0.047432 = (a/2)2
0.218 = (a/2)
a = 0.432 nm = 4.32 Å.
Radius of Chloride ion (r–) = 0.154 nm
Distance between the centres of the Chloride ions = 2 x 0.154 = 0.308 nm
Let the edge length of cube = a
Distance between Rb+ and Cl– ions = a/2
Therefore, the distance between Cl– ions = (2 x (a/2)2)1/2
0.308 = (2 x (a/2)2)1/2
0.094864 = 2 x (a/2)2
0.047432 = (a/2)2
0.218 = (a/2)
a = 0.432 nm = 4.32 Å.
Free Test
FREE
| Start Free Test |
Community Answer
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. ...
The unit cell edge length for RbCl can be determined by considering the arrangement of the chloride ions in the crystal structure.
1. Crystal Structure:
RbCl has a NaCl-like structure, which means that it adopts a face-centered cubic (FCC) arrangement. In this arrangement, each chloride ion is surrounded by 6 neighboring chloride ions and each rubidium ion is surrounded by 6 neighboring chloride ions.
2. Anion-Anion Contact:
In an FCC arrangement, the anion-anion contact occurs along the face diagonal of the unit cell. This means that the distance between the centers of two chloride ions in neighboring unit cells is equal to the face diagonal of the unit cell.
3. Calculation:
To calculate the face diagonal, we can consider a right-angled triangle formed by the face diagonal, the edge length of the unit cell, and the radius of the chloride ion.
Using the Pythagorean theorem, we have:
(face diagonal)^2 = (edge length)^2 + (edge length)^2
(face diagonal)^2 = 2(edge length)^2
face diagonal = sqrt(2) * edge length
Since the radius of the chloride ion is given as 1.54 Å, the face diagonal is equal to 2 * 1.54 Å = 3.08 Å.
4. Determining the Unit Cell Edge Length:
Now we can equate the face diagonal to sqrt(2) times the edge length of the unit cell and solve for the edge length:
3.08 Å = sqrt(2) * edge length
Dividing both sides of the equation by sqrt(2), we get:
edge length = 3.08 Å / sqrt(2) = 2.17 Å
5. Conversion to nm:
To convert the unit cell edge length from Ångstroms to nanometers, we divide by 10:
edge length = 2.17 Å / 10 = 0.217 nm
6. Answer:
Therefore, the unit cell edge length for RbCl is approximately 0.217 nm, which is closest to option 'C' (4.32 nm) in the given answer choices.
1. Crystal Structure:
RbCl has a NaCl-like structure, which means that it adopts a face-centered cubic (FCC) arrangement. In this arrangement, each chloride ion is surrounded by 6 neighboring chloride ions and each rubidium ion is surrounded by 6 neighboring chloride ions.
2. Anion-Anion Contact:
In an FCC arrangement, the anion-anion contact occurs along the face diagonal of the unit cell. This means that the distance between the centers of two chloride ions in neighboring unit cells is equal to the face diagonal of the unit cell.
3. Calculation:
To calculate the face diagonal, we can consider a right-angled triangle formed by the face diagonal, the edge length of the unit cell, and the radius of the chloride ion.
Using the Pythagorean theorem, we have:
(face diagonal)^2 = (edge length)^2 + (edge length)^2
(face diagonal)^2 = 2(edge length)^2
face diagonal = sqrt(2) * edge length
Since the radius of the chloride ion is given as 1.54 Å, the face diagonal is equal to 2 * 1.54 Å = 3.08 Å.
4. Determining the Unit Cell Edge Length:
Now we can equate the face diagonal to sqrt(2) times the edge length of the unit cell and solve for the edge length:
3.08 Å = sqrt(2) * edge length
Dividing both sides of the equation by sqrt(2), we get:
edge length = 3.08 Å / sqrt(2) = 2.17 Å
5. Conversion to nm:
To convert the unit cell edge length from Ångstroms to nanometers, we divide by 10:
edge length = 2.17 Å / 10 = 0.217 nm
6. Answer:
Therefore, the unit cell edge length for RbCl is approximately 0.217 nm, which is closest to option 'C' (4.32 nm) in the given answer choices.
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer?
Question Description
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer?.
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer?.
Solutions for Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 , what is the unit cell edge length for RbCl? (Assuming anion-anion contact)a)4.25 b)4.78 c)4.32 d)5.14 Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup