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The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 Å. The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal is
- a)3.25 Å
- b)2.545 Å
- c)0.415 Å
- d)1.315 Å
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The diffraction pattern of copper metal was measured with X-ray radiat...
In order to calculate the lattice spacing of the copper metal, we can use the Bragg's Law equation:
n * λ = 2 * d * sin(θ)
where:
- n is the order of diffraction (in this case, n = 1 for the first order)
- λ is the wavelength of the X-ray radiation (in this case, λ = 1.315 Å)
- d is the lattice spacing we want to calculate
- θ is the angle of diffraction (in this case, θ = 2θ)
Since the Bragg diffraction peak was found at an angle 2θ, we need to divide it by 2 to obtain the angle θ.
Let's assume that the angle 2θ is given in degrees. We can convert it to radians by multiplying by π/180.
θ = 2θ * π/180
Now, we can rearrange the equation to solve for d:
d = n * λ / (2 * sin(θ))
Substituting the given values:
n = 1
λ = 1.315 Å
θ = 2θ * π/180
we can calculate the lattice spacing.
n * λ = 2 * d * sin(θ)
where:
- n is the order of diffraction (in this case, n = 1 for the first order)
- λ is the wavelength of the X-ray radiation (in this case, λ = 1.315 Å)
- d is the lattice spacing we want to calculate
- θ is the angle of diffraction (in this case, θ = 2θ)
Since the Bragg diffraction peak was found at an angle 2θ, we need to divide it by 2 to obtain the angle θ.
Let's assume that the angle 2θ is given in degrees. We can convert it to radians by multiplying by π/180.
θ = 2θ * π/180
Now, we can rearrange the equation to solve for d:
d = n * λ / (2 * sin(θ))
Substituting the given values:
n = 1
λ = 1.315 Å
θ = 2θ * π/180
we can calculate the lattice spacing.
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The diffraction pattern of copper metal was measured with X-ray radiat...
Concept:
Bragg’s Law states that when an X-ray beam are allowed to scatter through a crystalline surface, its angle of incidence θ will reflect with some angle of scattering θ. And when the path difference d is equal to a whole number n, of wavelength.
It can be represented as
2dsinθ =nλ
Calculation:
Given:
λ = 1.315 Å, n = 1,
2θ = 60°
θ = 30°
From Bragg’s law:
2d sin θ = nλ
2 × d × sin 30° = 1 × 1.315
Bragg’s Law states that when an X-ray beam are allowed to scatter through a crystalline surface, its angle of incidence θ will reflect with some angle of scattering θ. And when the path difference d is equal to a whole number n, of wavelength.
It can be represented as
2dsinθ =nλ
Calculation:
Given:
λ = 1.315 Å, n = 1,
2θ = 60°
θ = 30°
From Bragg’s law:
2d sin θ = nλ
2 × d × sin 30° = 1 × 1.315
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The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer?
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The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer?.
The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The diffraction pattern of copper metal was measured with X-ray radiation of wavelength of 1.315 . The first order Bragg diffraction peak was found at an angle 2θ of 60°. The d-spacing between the diffracting planes in the copper metal isa)3.25 b)2.545 c)0.415 d)1.315 Correct answer is option 'D'. Can you explain this answer?.
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