A moving coil of a meter has 250 turns and a length and depth of 40 mm...
Given, N = 250, L = 40 x 10-3, d = 30 x 10-3m, I = 160 x 10-3A, B = 450 x 10-3 T
Torque = 250 x 450 x 10-3 x 40 x 10-3 × 30 x 10-3 x 160 x 10-3
= 200 x 10-6 N-m = 0.0216 N-m.
A moving coil of a meter has 250 turns and a length and depth of 40 mm...
To calculate the torque on the coil, we can use the formula:
Torque = NIABsinθ
where N is the number of turns in the coil, I is the current passing through the coil, A is the area of the coil, B is the magnetic field strength, and θ is the angle between the normal to the coil and the magnetic field lines.
Let's calculate each parameter step by step:
1. Number of turns (N): Given as 250.
2. Current (I): Given as 160 mA. Convert it to Amperes by dividing by 1000:
I = 160 mA / 1000 = 0.16 A.
3. Area of the coil (A): The coil has a rectangular shape with length and depth given as 40 mm and 30 mm respectively. Convert the dimensions to meters:
Length = 40 mm = 40/1000 = 0.04 m
Depth = 30 mm = 30/1000 = 0.03 m
The area can be calculated as the product of length and depth:
A = 0.04 m * 0.03 m = 0.0012 m^2.
4. Magnetic field strength (B): Given as 450 mT. Convert it to Tesla by dividing by 1000:
B = 450 mT / 1000 = 0.45 T.
5. Angle (θ): The coil is positioned in a uniform radial flux density, which means the angle between the normal to the coil and the magnetic field lines is 90 degrees. Since sin(90) = 1, we can ignore this term in the calculation.
Now, we can substitute the values into the torque formula:
Torque = (250 turns) * (0.16 A) * (0.0012 m^2) * (0.45 T) * 1
= 0.0216 N-m
Therefore, the torque on the coil is 0.0216 N-m, which corresponds to option A.