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The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.
The number of distinct values that B can possibly take after the execution is __________.
Correct answer is '3'. Can you explain this answer?
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The following two functions P1 and P2 that share a variable B with an ...
Initial value of B is 2 //value stored in main memory
Value of B = 4
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
execute P1()
P1 ( ) {
C = B – 1; // C = 3 – 1 = 2
B = 2 * C; // B = 2 × 2 = 4
}
write the value of B = 4 is memory.
Distinct value of B is 4.
Value of B =3
First Execute P1()
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 =2
}
write the value of B = 2 to memory
then execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
One of the distinct values of B is 3.
Value of B = 2
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
//don’t write to memory
execute P1() // with initial value of B = 2
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 = 2
}
write the value B = 3 by P2() in memory.
overwrite the value written by P2() as B = 2 by P1() in memory.
One of the distinct values of B is 2.
Therefore, the distinct values of B are 2, 3 and 4.
The number of distinct values that B can possibly take after the execution is 3.
Value of B = 4
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
execute P1()
P1 ( ) {
C = B – 1; // C = 3 – 1 = 2
B = 2 * C; // B = 2 × 2 = 4
}
write the value of B = 4 is memory.
Distinct value of B is 4.
Value of B =3
First Execute P1()
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 =2
}
write the value of B = 2 to memory
then execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
One of the distinct values of B is 3.
Value of B = 2
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
//don’t write to memory
execute P1() // with initial value of B = 2
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 = 2
}
write the value B = 3 by P2() in memory.
overwrite the value written by P2() as B = 2 by P1() in memory.
One of the distinct values of B is 2.
Therefore, the distinct values of B are 2, 3 and 4.
The number of distinct values that B can possibly take after the execution is 3.
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Community Answer
The following two functions P1 and P2 that share a variable B with an ...
Initial value of B is 2 //value stored in main memory
Value of B = 4
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
execute P1()
P1 ( ) {
C = B – 1; // C = 3 – 1 = 2
B = 2 * C; // B = 2 × 2 = 4
}
write the value of B = 4 is memory.
Distinct value of B is 4.
Value of B =3
First Execute P1()
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 =2
}
write the value of B = 2 to memory
then execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
One of the distinct values of B is 3.
Value of B = 2
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
//don’t write to memory
execute P1() // with initial value of B = 2
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 = 2
}
write the value B = 3 by P2() in memory.
overwrite the value written by P2() as B = 2 by P1() in memory.
One of the distinct values of B is 2.
Therefore, the distinct values of B are 2, 3 and 4.
The number of distinct values that B can possibly take after the execution is 3.
Value of B = 4
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
execute P1()
P1 ( ) {
C = B – 1; // C = 3 – 1 = 2
B = 2 * C; // B = 2 × 2 = 4
}
write the value of B = 4 is memory.
Distinct value of B is 4.
Value of B =3
First Execute P1()
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 =2
}
write the value of B = 2 to memory
then execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
write the value of B = 3 to memory
One of the distinct values of B is 3.
Value of B = 2
First execute P2()
P2 ( ) {
D = 2 * B; // 2 × 2 = 4
B = D – 1; // B = 4 – 1 = 3
}
//don’t write to memory
execute P1() // with initial value of B = 2
P1 ( ) {
C = B – 1; // C = 2 – 1 = 1
B = 2 * C; // B = 2 × 1 = 2
}
write the value B = 3 by P2() in memory.
overwrite the value written by P2() as B = 2 by P1() in memory.
One of the distinct values of B is 2.
Therefore, the distinct values of B are 2, 3 and 4.
The number of distinct values that B can possibly take after the execution is 3.
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The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer?
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The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer?.
The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer?.
Solutions for The following two functions P1 and P2 that share a variable B with an initial value of 2 execute concurrently.The number of distinct values that B can possibly take after the execution is __________.Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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