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To obtain a string of n Terminals from a given Chomsky normal form grammar, the number of productions to be used is:
- a)2n − 1
- b)2n
- c)n + 1
- d)n2
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
To obtain a string of n Terminals from a given Chomsky normal form gra...
Concept:
Chomsky normal form
S → AB
A → a
B → b
Length of string = n
Chomsky normal form
S → AB
A → a
B → b
Length of string = n
Length of the derivate of string n in context free grammar:
2|n| – 1
2|n| – 1
Example:
If we need to generate ab (string of length 2)
S → AB
S → aB
S → ab
Number of steps = 2 × 2 – 1 = 3
If we need to generate ab (string of length 2)
S → AB
S → aB
S → ab
Number of steps = 2 × 2 – 1 = 3
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To obtain a string of n Terminals from a given Chomsky normal form gra...
The correct answer is b) 2n-1.
In Chomsky normal form grammar, all productions are of the form A -> BC or A -> a, where A, B, and C are non-terminals and a is a terminal.
To obtain a string of n terminals, we need to use n-1 productions of the form A -> BC and one production of the form A -> a.
Therefore, the total number of productions needed is (n-1) + 1 = n.
In Chomsky normal form grammar, all productions are of the form A -> BC or A -> a, where A, B, and C are non-terminals and a is a terminal.
To obtain a string of n terminals, we need to use n-1 productions of the form A -> BC and one production of the form A -> a.
Therefore, the total number of productions needed is (n-1) + 1 = n.
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To obtain a string of n Terminals from a given Chomsky normal form grammar, the number of productions to be used is:a)2n − 1b)2nc)n + 1d)n2Correct answer is option 'A'. Can you explain this answer?
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