Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > An iron-cored coil has an inductance of 4 H. ...
Start Learning for Free
An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:
- a)400
- b)200
- c)20
- d)40
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An iron-cored coil has an inductance of 4 H. If the reluctance of the ...
Concept:
Self-Inductance
Self-Inductance
Here, A = Area
N = Number of turns
l = Length of coil
magnetic flux 
Reluctance s = N2 / L.......(i)
Calculation:
L = 4 H, s = 100 AT / Wb
From equation (i)
N = √4×100
= 20
Most Upvoted Answer
An iron-cored coil has an inductance of 4 H. If the reluctance of the ...
To find the number of turns in the coil, we can use the formula for inductance:
L = (N^2 * μ0 * A) / l
where L is the inductance, N is the number of turns, μ0 is the permeability of free space, A is the cross-sectional area of the coil, and l is the length of the coil.
Given that the inductance is 4 H and the reluctance is 100 AT/Wb, we can rearrange the formula to solve for N:
N = √(L * l / (μ0 * A))
Given that the reluctance is equal to 100 AT/Wb, we know that the permeability of free space can be calculated as:
μ0 = 1 / (100 * 10^-8) = 10^6 Wb/ATm
Let's assume a length of 1 meter for the coil (l = 1 m). Now we need to find the cross-sectional area of the coil.
Since the reluctance is given in AT/Wb and the formula for reluctance is:
Reluctance = l / (μ0 * A)
We can rearrange this formula to solve for A:
A = l / (μ0 * Reluctance)
Plugging in the values, we get:
A = 1 / (10^6 * 100) = 10^-8 m^2
Now we can substitute the values of L, l, μ0, and A into the formula for N:
N = √(4 * 1 / (10^6 * 10^-8))
Simplifying, we get:
N = √(40)
N ≈ 6.32
Since the number of turns must be an integer, the closest option is 20 (option C), which is the correct answer.
L = (N^2 * μ0 * A) / l
where L is the inductance, N is the number of turns, μ0 is the permeability of free space, A is the cross-sectional area of the coil, and l is the length of the coil.
Given that the inductance is 4 H and the reluctance is 100 AT/Wb, we can rearrange the formula to solve for N:
N = √(L * l / (μ0 * A))
Given that the reluctance is equal to 100 AT/Wb, we know that the permeability of free space can be calculated as:
μ0 = 1 / (100 * 10^-8) = 10^6 Wb/ATm
Let's assume a length of 1 meter for the coil (l = 1 m). Now we need to find the cross-sectional area of the coil.
Since the reluctance is given in AT/Wb and the formula for reluctance is:
Reluctance = l / (μ0 * A)
We can rearrange this formula to solve for A:
A = l / (μ0 * Reluctance)
Plugging in the values, we get:
A = 1 / (10^6 * 100) = 10^-8 m^2
Now we can substitute the values of L, l, μ0, and A into the formula for N:
N = √(4 * 1 / (10^6 * 10^-8))
Simplifying, we get:
N = √(40)
N ≈ 6.32
Since the number of turns must be an integer, the closest option is 20 (option C), which is the correct answer.
Free Test
FREE
| Start Free Test |
Community Answer
An iron-cored coil has an inductance of 4 H. If the reluctance of the ...
Concept:
Self-Inductance
Self-Inductance
Here, A = Area
N = Number of turns
l = Length of coil
magnetic flux
Reluctance s = N2 / L.......(i)
Calculation:
L = 4 H, s = 100 AT / Wb
From equation (i)
N = √4×100
= 20
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Top Courses for Electrical Engineering (EE)View all
Question Description
An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer?.
An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer?.
Solutions for An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer?, a detailed solution for An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An iron-cored coil has an inductance of 4 H. If the reluctance of the flux path is 100 AT/Wb, then the number of turns in the coil is:a)400b)200c)20d)40Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup