Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  Which of the following statement is true for ... Start Learning for Free
Which of the following statement is true for buddy system allocators?
  1. Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation.
  2. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list.
  3. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request.
  4. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.
  • a)
    1 only
  • b)
    1,2 only
  • c)
    2,3 only
  • d)
    1,4 only
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Which of the following statement is true for buddy system allocators? ...
Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.
Free Test
Community Answer
Which of the following statement is true for buddy system allocators? ...
Explanation:

1. Buddy System Allocator:
- Buddy System allocators split and recombine memory blocks in a predetermined manner during allocation and deallocation.
- This system involves splitting larger blocks into smaller blocks to fulfill memory requests and recombining smaller blocks into larger blocks when memory is released.

4. Process of Allocation:
- When a request is made for m bytes, the system finds the smallest power of 2 that is greater than or equal to m.
- If the list is empty for the required size, it checks the lists for blocks of size 2^(i+1).
- It takes one block off this list and splits it into two halves of size 2^i.
- One of these blocks is put into the free list of size 2^i, and the other block is used to satisfy the memory request.
Therefore, the correct statement for buddy system allocators is option 'D' - 1,4 only. It involves splitting and recombining memory blocks based on powers of 2 to efficiently manage memory allocation and deallocation.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer?
Question Description
Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Which of the following statement is true for buddy system allocators? Buddy System splits and recombines memory blocks in a predetermined manner during allocation and deallocation. No splitting of blocks takes place, also no effort is made to coalesce adjoining blocks to form larger blocks; when released, a block is simply returned to its free list. When a request is made for m bytes, the allocator first check the free list containing blocks whose size is 2i for the smallest value of i such that 2i ≥ m.if the free list is empty ,it checks the list containing blocks that are higher the next higher power of 2 in size on so on. an entire block is allocated to a request. When a request is made for m bytes. the system finds the smallest power of 2 that is ≥ m. Let this be 2i.if the list is empty, it checks the lists for block of size 2i+1.it takes one block off this list and splits it into two halves of size 2i.it put one of these blocks into the free list of size 2i,and uses the other block to satisfy the request.a)1 onlyb)1,2 onlyc)2,3 onlyd)1,4 onlyCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev