A system uses FIFO policy for page replacement. It has 4 page frames w...
Given that page frame size = 4
As there are 100 distinct pages which are first accessed → 100 page faults
when it accesses the same 100 pages but now in the reverse order → (100-4)
Because page frame size is four.
There fore, Total number of page faults = 100+ (100-4)= 196
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A system uses FIFO policy for page replacement. It has 4 page frames w...
Given that page frame size = 4
As there are 100 distinct pages which are first accessed → 100 page faults
when it accesses the same 100 pages but now in the reverse order → (100-4)
Because page frame size is four.
There fore, Total number of page faults = 100+ (100-4)= 196
A system uses FIFO policy for page replacement. It has 4 page frames w...
First-in, First-out (FIFO) Page Replacement Policy:
FIFO is a page replacement policy in which the page that is loaded first into the memory is the first one to be replaced when a page fault occurs. In this policy, a queue is used to keep track of the loaded pages, and the page at the front of the queue is the one to be replaced.
Given Information:
- Number of page frames available = 4
- The system first accesses 100 distinct pages in some order.
- The system then accesses the same 100 pages, but in reverse order.
Analysis:
1. Initially, all the page frames are empty (no pages loaded).
2. As the system accesses the first 100 distinct pages, each page will cause a page fault because there are no pages loaded in the memory.
3. The page faults will continue until all the page frames are filled with the distinct pages.
4. Once all the page frames are filled, the next accessed page will cause a page fault, and the page at the front of the queue (the oldest loaded page) will be replaced.
5. As the system accesses the same 100 pages in reverse order, the page faults will occur only when the next accessed page is not already present in the memory.
Calculating the Page Faults:
1. Initially, the first 100 distinct pages will cause page faults until all the page frames are filled. So, there will be 100 page faults.
2. After the page frames are filled, the next accessed page will cause a page fault, and the oldest page (at the front of the queue) will be replaced with the new page.
3. Since there are 100 pages, and each page will cause a page fault as it is not already present in the memory, there will be 100 page faults during the reverse order access.
4. Therefore, the total number of page faults will be 100 (distinct pages access) + 100 (reverse order access) = 200.
The correct answer is not among the options given. However, the closest option to the correct answer is option 'A' (196), which is the result of subtracting 4 (the initial 4 empty page frames) from the calculated 200 page faults.