Class 6 Exam > Class 6 Questions > Consider a system with byte-addressable memor...
Start Learning for Free
Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.
Correct answer is '4'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Consider a system with byte-addressable memory, 32-bit logical address...
Given information:
- Byte-addressable memory
- 32-bit logical addresses
- 4 kilobyte page size
- Page table entries of 4 bytes each
Calculating the number of pages:
- 32-bit logical addresses can address 2^32 bytes of memory
- Dividing this by the page size of 4 kilobytes (or 2^12 bytes) gives 2^20 pages
Calculating the size of the page table:
- Each page table entry is 4 bytes
- Multiplying this by the number of pages gives 4 * 2^20 bytes
- Converting this to megabytes gives 4 MB
Therefore, the size of the page table in the system is 4 megabytes.
- Byte-addressable memory
- 32-bit logical addresses
- 4 kilobyte page size
- Page table entries of 4 bytes each
Calculating the number of pages:
- 32-bit logical addresses can address 2^32 bytes of memory
- Dividing this by the page size of 4 kilobytes (or 2^12 bytes) gives 2^20 pages
Calculating the size of the page table:
- Each page table entry is 4 bytes
- Multiplying this by the number of pages gives 4 * 2^20 bytes
- Converting this to megabytes gives 4 MB
Therefore, the size of the page table in the system is 4 megabytes.
Community Answer
Consider a system with byte-addressable memory, 32-bit logical address...
Data
1 word (W) = 1 byte (B)
Logical address = 232 B
page size = 4 KB = 212 B
page table entry (PTE) = y B
1 word (W) = 1 byte (B)
Logical address = 232 B
page size = 4 KB = 212 B
page table entry (PTE) = y B
Formula:
Page table size (PTS) = number of pages × y
Page table size (PTS) = number of pages × y
Calculation:
number of pages = 232/212 = 220
Page table size (PTS) = number of pages × y
PTS = 220 × 4B
∴ PTS = 4 MB
Important points
1 MB = 220 B
where B stands for byte
number of pages = 232/212 = 220
Page table size (PTS) = number of pages × y
PTS = 220 × 4B
∴ PTS = 4 MB
Important points
1 MB = 220 B
where B stands for byte
Attention Class 6 Students!
To make sure you are not studying endlessly, EduRev has designed Class 6 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 6.
|
Explore Courses for Class 6 exam
|
|
Similar Class 6 Doubts
Top Courses for Class 6View all
Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer?
Question Description
Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? for Class 6 2024 is part of Class 6 preparation. The Question and answers have been prepared according to the Class 6 exam syllabus. Information about Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Class 6 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer?.
Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? for Class 6 2024 is part of Class 6 preparation. The Question and answers have been prepared according to the Class 6 exam syllabus. Information about Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Class 6 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer?.
Solutions for Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 6.
Download more important topics, notes, lectures and mock test series for Class 6 Exam by signing up for free.
Here you can find the meaning of Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer?, a detailed solution for Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? has been provided alongside types of Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a system with byte-addressable memory, 32-bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is _______.Correct answer is '4'. Can you explain this answer? tests, examples and also practice Class 6 tests.
|
|
Explore Courses for Class 6 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup