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Consider the process track request are 98, 183, 37, 122, 14, 124, 14, 124, 65, 67 and the initial seek is 53. What is the total number of seeks for the C-Look algorithm?
    Correct answer is '322'. Can you explain this answer?
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    Most Upvoted Answer
    Consider the process track request are 98, 183, 37, 122, 14, 124, 14, ...
    The given data,
    The process track request are= 98, 183, 37, 122, 14, 124, 14, 124, 65, 67 
    The initial seek = 53
    C-Look algorithm:
    Total number of seeks= ( 183-53 )+(183-14) +(37-14)
    Total number of seeks= 322
    Hence the correct answer is 322.
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    Community Answer
    Consider the process track request are 98, 183, 37, 122, 14, 124, 14, ...
    Introduction:
    The C-Look algorithm is a disk scheduling algorithm used to determine the order in which disk requests are serviced. It is a variation of the C-Scan algorithm and is commonly used in disk drives.

    Given:
    - Process track requests: 98, 183, 37, 122, 14, 124, 14, 124, 65, 67
    - Initial seek: 53

    Steps to calculate the total number of seeks:

    1. Sort the process track requests:
    Arrange the process track requests in ascending order to get a clear understanding of the disk locations being accessed.

    Sorted process track requests: 14, 14, 37, 65, 67, 98, 122, 124, 124, 183

    2. Split the process track requests into two halves:
    Split the sorted process track requests into two parts based on the initial seek location. One part will consist of requests to the right of the initial seek, and the other part will consist of requests to the left.

    Left requests: 14, 14, 37
    Right requests: 65, 67, 98, 122, 124, 124, 183

    3. Calculate the total number of seeks:
    3.1. Calculate the seeks for the right requests:
    - As the C-Look algorithm moves towards the right, it services the requests in ascending order until the highest request is reached.
    - Calculate the seeks by subtracting the current request from the next request and taking the absolute value.
    - Sum up all the seeks for the right requests.

    Seeks for the right requests:
    (65-53) + (67-65) + (98-67) + (122-98) + (124-122) + (124-124) + (183-124) = 12 + 2 + 31 + 24 + 2 + 0 + 59 = 130

    3.2. Calculate the seeks for the left requests:
    - Since the C-Look algorithm doesn't go back to the beginning, we don't consider the seeks for the left requests.

    4. Calculate the total number of seeks:
    Total number of seeks = Seeks for the right requests + Seeks for the left requests = 130 + 0 = 130

    Final answer:
    The total number of seeks for the C-Look algorithm is 130.
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    Consider a storage disk with 4 platters (numbered as 0, 1, 2 and 3), 200 cylinders (numbered as 0, 1, … , 199), and 256 sectors per track (numbered as 0, 1, … , 255). The following 6 disk requests of the form [sector number, cylinder number, platter number] are received by the disk controller at the same time: [120, 72, 2] , [180, 134, 1] , [60, 20, 0] , [212, 86, 3] , [56, 116, 2] , [118, 16, 1] Currently the head is positioned at sector number 100 of cylinder 80, and is moving towards higher cylinder numbers. The average power dissipation in moving the head over 100 cylinders is 20 milliwatts and for reversing the direction of the head movement once is 15 milliwatts. Power dissipation associated with rotational latency and switching of head between different platters is negligible. The total power consumption in milliwatts to satisfy all of the above disk requests using the Shortest Seek Time First disk scheduling algorithm is _______. Correct answer is '85'. Can you explain this answer?

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    Consider the process track request are 98, 183, 37, 122, 14, 124, 14, 124, 65, 67 and the initial seek is 53. What is the total number of seeks for the C-Look algorithm?Correct answer is '322'. Can you explain this answer?
    Question Description
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