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Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)
Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?
  • a)
    T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicity
  • b)
    Schedule S is non-recoverable and cannot ensure transaction atomicity
  • c)
    Only T2 must be aborted and then re-started to ensure transaction atomicity
  • d)
    Schedule S is recoverable and can ensure atomicity and nothing else needs to be done
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider the following partial Schedule S involving two transactions T...
Option 1: Incorrect
As, it is not giving any surety about T1, there is no commit in T1.  Rolling back of T2 may not be required in this.
Option 2: Correct
In given schedule, T2 is reading data item A that is written by T1 so it means commit of T1 must before the commit of T2, but here in this schedule it is not happening. So, this is non – recoverable schedule. In this after T1 fails, if we want to undo all the operations, still we cannot undo a committed transaction. So, it cannot ensure transaction atomicity.
Option 3: Incorrect
It is redoing all the operations of T2. But in this, it is reading data item A that is written by T1 and T1 is not committed. So, it results in dirty read problem.
Option 4: Incorrect
Since Schedule S is non – recoverable. So, it is incorrect. Also, it cannot ensure atomicity.
 
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Community Answer
Consider the following partial Schedule S involving two transactions T...
Option 1: Incorrect
As, it is not giving any surety about T1, there is no commit in T1.  Rolling back of T2 may not be required in this.
Option 2: Correct
In given schedule, T2 is reading data item A that is written by T1 so it means commit of T1 must before the commit of T2, but here in this schedule it is not happening. So, this is non – recoverable schedule. In this after T1 fails, if we want to undo all the operations, still we cannot undo a committed transaction. So, it cannot ensure transaction atomicity.
Option 3: Incorrect
It is redoing all the operations of T2. But in this, it is reading data item A that is written by T1 and T1 is not committed. So, it results in dirty read problem.
Option 4: Incorrect
Since Schedule S is non – recoverable. So, it is incorrect. Also, it cannot ensure atomicity.
 
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Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer?
Question Description
Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Consider the following partial Schedule S involving two transactions T1 and T2. Only the read and the write operations have been shown. The read operation on data item P is denoted by read(P) and the write operation on data item P is denoted by write(P)Suppose that the transaction T1 fails immediately after time instance 9. Which one of the following statements is correct?a)T2 must be aborted and then both T1 and T2 must be re-started to ensure transaction atomicityb)Schedule S is non-recoverable and cannot ensure transaction atomicityc)Only T2 must be aborted and then re-started to ensure transaction atomicityd)Schedule S is recoverable and can ensure atomicity and nothing else needs to be doneCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
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