Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Questions  >  The Nyquist plot of the transfer functionDoes... Start Learning for Free
The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) is
  • a)
    stable for K = 10 and stable for K = 100
  • b)
    stable for K = 10 and unstable for K = 100
  • c)
    unstable for K = 10 and stable for K = 100
  • d)
    unstable for K = 100 and unstable for K = 100
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The Nyquist plot of the transfer functionDoes not encircle the point (...
Concept:
For Nyquist stability
N = P
P = Number of open-loop poles in RHS of s-plane
N = Number of encirclement about the point (-1 + j0)
N = +ve for anticlockwise
N = -ve for clockwise enduement
Calculation:
The polar plot is drawn as:

 
Let two points A and B representing -1 + j0 for different values of K,
The Nyquist plot is not encircling -1 + j 0 at A, i.e, K = 10
at B, the Nyquist plot is encircling -1 + j 0 i. e, K = 100
Let us now find the stability for K = 10 and K = 100 using Nyquist
Case: 1
K = 10
N = P - Z
Z = P - N

The Routh table can be drawn as follows:

No sign change, hence P = 0 and also N = 0
∴ Z = 0 → CLTP is stable
Case: 2
Z = P - N
N = -2 (two clockwise encirclement)
∴ Z = 2.
hence, CLTP is unstable.
Free Test
Community Answer
The Nyquist plot of the transfer functionDoes not encircle the point (...
Concept:
For Nyquist stability
N = P
P = Number of open-loop poles in RHS of s-plane
N = Number of encirclement about the point (-1 + j0)
N = +ve for anticlockwise
N = -ve for clockwise enduement
Calculation:
The polar plot is drawn as:

 
Let two points A and B representing -1 + j0 for different values of K,
The Nyquist plot is not encircling -1 + j 0 at A, i.e, K = 10
at B, the Nyquist plot is encircling -1 + j 0 i. e, K = 100
Let us now find the stability for K = 10 and K = 100 using Nyquist
Case: 1
K = 10
N = P - Z
Z = P - N

The Routh table can be drawn as follows:

No sign change, hence P = 0 and also N = 0
∴ Z = 0 → CLTP is stable
Case: 2
Z = P - N
N = -2 (two clockwise encirclement)
∴ Z = 2.
hence, CLTP is unstable.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer?
Question Description
The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer?.
Solutions for The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The Nyquist plot of the transfer functionDoes not encircle the point (–1 + j0) for K = 10 but does encircle the point (-1 + j0) for K = 100 . Then the closed-loop system (having unity gain feedback) isa)stable for K = 10 and stable for K = 100b)stable for K = 10 and unstable for K = 100c)unstable for K = 10 and stable for K = 100d)unstable for K = 100 and unstable for K = 100Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev