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The loop transfer function of a negative feedback system is
The Nyquist plot for the above system
The Nyquist plot for the above system- a)encircles (-1 + j0) point once in the clockwise direction
- b)encircles (-1 + j0) point once in the counter clockwise direction
- c)does not encircle (-1 + j0) point
- d)encircles (-1 + j0) point twice in the counter clockwise direction
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The loop transfer function of a negative feedback system isThe Nyquist...
Concept:
Nyquist stability criterion:
N = P – Z
N is the number of encirclements of (-1+j0) point by the Nyquist contour in an anticlockwise direction.
P is the open-loop RHP poles
Z is the closed-loop RHP poles
Calculation:
Number of open loops RHP pole (P) = 1
Characteristic equation: 1 + G(s) H(s) = 0
⇒ s2 – 2s + 1 = 0
Number of open loops RHP pole (P) = 1
Characteristic equation: 1 + G(s) H(s) = 0
⇒ s2 – 2s + 1 = 0
⇒ s = 1, 1
Number of closed loop RHP poles (Z) = 2
From Nyquist stability condition,
Number of encirclements N = P – Z = 1 – 2 = -1
Therefore, the Nyquist plot encircles (–1, 0) once in the clockwise direction.
Most Upvoted Answer
The loop transfer function of a negative feedback system isThe Nyquist...
Concept:
Nyquist stability criterion:
N = P – Z
N is the number of encirclements of (-1+j0) point by the Nyquist contour in an anticlockwise direction.
P is the open-loop RHP poles
Z is the closed-loop RHP poles
Calculation:
Number of open loops RHP pole (P) = 1
Characteristic equation: 1 + G(s) H(s) = 0
⇒ s2 – 2s + 1 = 0
Number of open loops RHP pole (P) = 1
Characteristic equation: 1 + G(s) H(s) = 0
⇒ s2 – 2s + 1 = 0
⇒ s = 1, 1
Number of closed loop RHP poles (Z) = 2
From Nyquist stability condition,
Number of encirclements N = P – Z = 1 – 2 = -1
Therefore, the Nyquist plot encircles (–1, 0) once in the clockwise direction.
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The loop transfer function of a negative feedback system isThe Nyquist plot for the above systema)encircles (-1 + j0) point once in the clockwise directionb)encircles (-1 + j0) point once in the counter clockwise directionc)does not encircle (-1 + j0) pointd)encircles (-1 + j0) point twice in the counter clockwise directionCorrect answer is option 'A'. Can you explain this answer?
Question Description
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