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A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?
  • a)
    70
  • b)
    98
  • c)
    126
  • d)
    168
  • e)
    182
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A group of store managers must assemble 280 displays for an upcoming s...
To solve this problem, we can break it down into smaller steps and calculate the number of displays assembled during each hour.

Step 1: Calculate the number of displays assembled in the first hour.
25% of 280 displays = (25/100) * 280 = 70 displays

Step 2: Calculate the number of displays remaining after the first hour.
280 displays - 70 displays = 210 displays

Step 3: Calculate the number of displays assembled in the second hour.
40% of the remaining 210 displays = (40/100) * 210 = 84 displays

Step 4: Calculate the number of displays remaining at the end of the second hour.
210 displays - 84 displays = 126 displays

Therefore, the answer is option 'C', 126 displays will not have been assembled by the end of the second hour.

Let's summarize the steps:

Step 1: Calculate the number of displays assembled in the first hour.
- 25% * 280 = 70 displays

Step 2: Calculate the number of displays remaining after the first hour.
- 280 - 70 = 210 displays

Step 3: Calculate the number of displays assembled in the second hour.
- 40% * 210 = 84 displays

Step 4: Calculate the number of displays remaining at the end of the second hour.
- 210 - 84 = 126 displays

Therefore, the correct answer is option 'C', 126 displays will not have been assembled by the end of the second hour.
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Community Answer
A group of store managers must assemble 280 displays for an upcoming s...
If, during the first hour, 25 percent of the total displays were assembled, then 280(0.25) = 70 displays were assembled, leaving 280 - 70 = 210 displays remaining to be assembled. Since 40 percent of the remaining displays were assembled during the second hour, 0.40(210) = 84 displays were assembled during the second hour. Thus, 70 + 84 = 154 displays were assembled during the first two hours and 280 - 154 = 126 displays had not been assembled by the end of the second hour.
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