A group of store managers must assemble 280 d...
A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?
• a)
70
• b)
98
• c)
126
• d)
168
• e)
182
A group of store managers must assemble 280 displays for an upcoming s...
If, during the first hour, 25 percent of the total displays were assembled, then 280(0.25) = 70 displays were assembled, leaving 280 - 70 = 210 displays remaining to be assembled. Since 40 percent of the remaining displays were assembled during the second hour, 0.40(210) = 84 displays were assembled during the second hour. Thus, 70 + 84 = 154 displays were assembled during the first two hours and 280 - 154 = 126 displays had not been assembled by the end of the second hour.
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A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?a)70b)98c)126d)168e)182Correct answer is option 'C'. Can you explain this answer?
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