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For the following equation, 2HBr(g) ⇌ H2(g) + Br2(g); are both KP and KC are equal?
- a)yes
- b)cannot say
- c)no
- d)depends on the temperature
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
For the following equation, 2HBr(g) H2(g) + Br2(g); are both KP and K...
We have here KC = [H2][Br2]/[HBr]2; KP = [pH2][pBr2]/[pHBr]2, where pH2 = [H2]RT, pBr2 = [Br2]RT and [pHBr] = [HBr]RT. So in this case as Δng = 0, where Δng = moles of products – moles of reactants which are in gaseous state only, both KP and KC are equal.
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Community Answer
For the following equation, 2HBr(g) H2(g) + Br2(g); are both KP and K...
Yes, both KP and KC are equal for the given equation 2HBr(g) ⇌ H2(g) + Br2(g).
Explanation:
- KP is the equilibrium constant expressed in terms of partial pressures, while KC is the equilibrium constant expressed in terms of molar concentrations.
- To determine whether KP and KC are equal, we need to write the expressions for both equilibrium constants and compare them.
Writing the expressions for KP and KC:
- KP is given by the ratio of the partial pressures of the products to the partial pressures of the reactants, each raised to the power of their stoichiometric coefficient. In this case, the expression for KP is:
KP = (P(H2) * P(Br2)) / (P(HBr)^2)
- KC is given by the ratio of the molar concentrations of the products to the molar concentrations of the reactants, each raised to the power of their stoichiometric coefficient. In this case, the expression for KC is:
KC = ([H2] * [Br2]) / ([HBr]^2)
Comparing the expressions for KP and KC:
- By comparing the expressions for KP and KC, we can see that the numerator and denominator are the same for both KP and KC. The only difference is the use of partial pressures in KP and molar concentrations in KC.
- Since the numerator and denominator are the same, it means that the ratio of the concentrations of the products to the concentrations of the reactants is the same as the ratio of the partial pressures of the products to the partial pressures of the reactants. Therefore, KP and KC are equal for this equation.
Conclusion:
- In conclusion, for the given equation 2HBr(g) ⇌ H2(g) + Br2(g), both KP and KC are equal. The expression for KP is (P(H2) * P(Br2)) / (P(HBr)^2) and the expression for KC is ([H2] * [Br2]) / ([HBr]^2). However, it is important to note that this equality only holds for this specific equation and may not be true for other chemical equations.
Explanation:
- KP is the equilibrium constant expressed in terms of partial pressures, while KC is the equilibrium constant expressed in terms of molar concentrations.
- To determine whether KP and KC are equal, we need to write the expressions for both equilibrium constants and compare them.
Writing the expressions for KP and KC:
- KP is given by the ratio of the partial pressures of the products to the partial pressures of the reactants, each raised to the power of their stoichiometric coefficient. In this case, the expression for KP is:
KP = (P(H2) * P(Br2)) / (P(HBr)^2)
- KC is given by the ratio of the molar concentrations of the products to the molar concentrations of the reactants, each raised to the power of their stoichiometric coefficient. In this case, the expression for KC is:
KC = ([H2] * [Br2]) / ([HBr]^2)
Comparing the expressions for KP and KC:
- By comparing the expressions for KP and KC, we can see that the numerator and denominator are the same for both KP and KC. The only difference is the use of partial pressures in KP and molar concentrations in KC.
- Since the numerator and denominator are the same, it means that the ratio of the concentrations of the products to the concentrations of the reactants is the same as the ratio of the partial pressures of the products to the partial pressures of the reactants. Therefore, KP and KC are equal for this equation.
Conclusion:
- In conclusion, for the given equation 2HBr(g) ⇌ H2(g) + Br2(g), both KP and KC are equal. The expression for KP is (P(H2) * P(Br2)) / (P(HBr)^2) and the expression for KC is ([H2] * [Br2]) / ([HBr]^2). However, it is important to note that this equality only holds for this specific equation and may not be true for other chemical equations.
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For the following equation, 2HBr(g) H2(g) + Br2(g); are both KP and KC are equal?a)yesb)cannot sayc)nod)depends on the temperatureCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For the following equation, 2HBr(g) H2(g) + Br2(g); are both KP and KC are equal?a)yesb)cannot sayc)nod)depends on the temperatureCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the following equation, 2HBr(g) H2(g) + Br2(g); are both KP and KC are equal?a)yesb)cannot sayc)nod)depends on the temperatureCorrect answer is option 'A'. Can you explain this answer?.
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