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The rate law for the reaction involved in inversion of cane sugar is R=k [C12H22O11] [H2O].
  • a)
    True
  • b)
    False
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The rate law for the reaction involved in inversion of cane sugar is R...
The reaction for the inversion of cane sugar is C12H22O11 + H2O → glucose + fructose.
In this reaction water is present in excess and belongs to a pseudo first order reaction, even though the molecularity is 2 the order of the reaction is 1 so the rate law R=k[C12H22O11].
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The rate law for the reaction involved in inversion of cane sugar is R...
The rate law for the reaction involved in inversion of cane sugar is R=k [C12H22O11] [H2O].
False

Explanation:
The rate law for a chemical reaction is an equation that relates the rate of the reaction to the concentrations of the reactants. It is determined experimentally and can be different for different reactions.

In the case of the inversion of cane sugar, the reaction involves the hydrolysis of sucrose (C12H22O11) in water (H2O) to produce glucose and fructose. The reaction is catalyzed by an acid or an enzyme.

The rate law for this reaction is not simply proportional to the concentrations of sucrose and water. The reaction mechanism involves multiple steps, and the rate-determining step may not involve both sucrose and water directly.

The correct rate law for the inversion of cane sugar is more complex and involves the concentrations of both sucrose and water, as well as the concentration of the acid or enzyme catalyst. The rate law can vary depending on the specific conditions of the reaction, such as the temperature and the concentration of the catalyst.

Therefore, the given rate law R=k [C12H22O11] [H2O] is incorrect for the inversion of cane sugar. The correct rate law would include additional terms for the catalyst and possibly other factors that affect the rate of the reaction.

In summary,
- The rate law for a chemical reaction relates the rate of the reaction to the concentrations of the reactants.
- The rate law for the inversion of cane sugar is more complex than simply proportional to the concentrations of sucrose and water.
- The given rate law R=k [C12H22O11] [H2O] is incorrect for the inversion of cane sugar.
- The correct rate law for the inversion of cane sugar would include additional terms for the catalyst and possibly other factors.
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Community Answer
The rate law for the reaction involved in inversion of cane sugar is R...
The reaction for the inversion of cane sugar is C12H22O11 + H2O → glucose + fructose.
In this reaction water is present in excess and belongs to a pseudo first order reaction, even though the molecularity is 2 the order of the reaction is 1 so the rate law R=k[C12H22O11].
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The rate law for the reaction involved in inversion of cane sugar is R=k [C12H22O11] [H2O].a)Trueb)FalseCorrect answer is option 'B'. Can you explain this answer?
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