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What time does it take for reactants to reduce to 3/4 of initial concentration if the rate constant is 7.5 x 10-3 s-1?
  • a)
    38.4s
  • b)
    40.2s
  • c)
    39.3s
  • d)
    36.8s
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What time does it take for reactants to reduce to 3/4 of initial conce...
Given,
K=7.5 x 10-3 s-1
K = (2.303/t) x log([R]0/[R])
t = (2.303/7.5 x 10-3) x log([100]/[25])
t = (2.303/7.5 x 10-3) x 0.6
t = 38.4s.
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Most Upvoted Answer
What time does it take for reactants to reduce to 3/4 of initial conce...
Given,
K=7.5 x 10-3 s-1
K = (2.303/t) x log([R]0/[R])
t = (2.303/7.5 x 10-3) x log([100]/[25])
t = (2.303/7.5 x 10-3) x 0.6
t = 38.4s.
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Community Answer
What time does it take for reactants to reduce to 3/4 of initial conce...
Initial conc.of Reactant is 100
remaining conc.of reactant is 75
then..aply the formula...
(2.303/7.5×10^-3)log(100/75
(0.000307)×1.23
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