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The bode magnitude plot for the transfer function V0(s)/Vi(s) of the circuit is as shown. The value of R is ______ Ω.(Round off to 2 decimal places.)
    Correct answer is between '0.09,0.11'. Can you explain this answer?
    Verified Answer
    The bode magnitude plot for the transfer functionV0(s)/Vi(s) of the ci...
    Given circuit,

    The transfer function for series RLC circuit by taking output voltage acroos the capacitor is given by,

    From the plot,
    20 log|Mr| = 26 dB
    |Mr| = 19.95
    19.95 × 0.5R = 1
    R = 0.1 Ω
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    The bode magnitude plot for the transfer functionV0(s)/Vi(s) of the ci...
    Given circuit,

    The transfer function for series RLC circuit by taking output voltage acroos the capacitor is given by,

    From the plot,
    20 log|Mr| = 26 dB
    |Mr| = 19.95
    19.95 × 0.5R = 1
    R = 0.1 Ω
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    The bode magnitude plot for the transfer functionV0(s)/Vi(s) of the circuit is as shown. The value of R is ______ Ω.(Round off to 2 decimal places.)Correct answer is between '0.09,0.11'. Can you explain this answer?
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    The bode magnitude plot for the transfer functionV0(s)/Vi(s) of the circuit is as shown. The value of R is ______ Ω.(Round off to 2 decimal places.)Correct answer is between '0.09,0.11'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The bode magnitude plot for the transfer functionV0(s)/Vi(s) of the circuit is as shown. The value of R is ______ Ω.(Round off to 2 decimal places.)Correct answer is between '0.09,0.11'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The bode magnitude plot for the transfer functionV0(s)/Vi(s) of the circuit is as shown. The value of R is ______ Ω.(Round off to 2 decimal places.)Correct answer is between '0.09,0.11'. Can you explain this answer?.
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