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If x+1/x = 3, find value of x^4+1/x^4.?
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If x+1/x = 3, find value of x^4+1/x^4.?
Answer is 47?x+1/x=3now finding d value of x^2+(1/x^2)x^2+(1/x^2)=7. (a)now v have to find d value of x^4+(1/x^4)so,x^4+(1/x^4)=(x^2)^2 + {1/(x^2)^2}=(x^2)^2 + {1/(x^2)^2} +2×(x^2)×(1/x^2) -2×(x^2)×(1/x^2)=(x^2+1/x^2)^2 -2from (a) we know d value of x^2+(1/x^2), so putting x^2+(1/x^2)=7therefore,(7^2)-249-2=47ans.
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If x+1/x = 3, find value of x^4+1/x^4.?
47
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If x+1/x = 3, find value of x^4+1/x^4.?
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