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On what slope a 3 m wide rectangular channel (n= 0.014) should be constructed so that critical flow will occur at a normal depth of 1.2 m?
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On what slope a 3 m wide rectangular channel (n= 0.014) should be cons...
Calculation of Slope for Critical Flow in a Rectangular Channel

To determine the slope of a rectangular channel that will result in critical flow at a normal depth of 1.2 m, the following steps can be taken:

Step 1: Identify the necessary information

In this problem, the following information is given:

- Width of the rectangular channel (B) = 3 m
- Manning's roughness coefficient (n) = 0.014
- Normal depth (y) = 1.2 m

Step 2: Calculate the hydraulic radius (R)

The hydraulic radius of a rectangular channel can be calculated using the following formula:

R = (B x y) / (2 x y)

Substituting the given values, we get:

R = (3 x 1.2) / (2 x 1.2) = 1.5 m

Step 3: Calculate the critical depth (yc)

The critical depth of flow in a rectangular channel can be calculated using the following formula:

yc = B / (2.8 x (n)^0.5)

Substituting the given values, we get:

yc = 3 / (2.8 x (0.014)^0.5) = 1.52 m

Step 4: Determine the slope (S)

The slope of the rectangular channel can be calculated using the following formula:

S = (yc - y) / L

where L is the length of the channel.

Since the length of the channel is not given, we can assume a value of 100 m.

Substituting the given and assumed values, we get:

S = (1.52 - 1.2) / 100 = 0.0032 or 0.32%

Therefore, the slope of the rectangular channel that will result in critical flow at a normal depth of 1.2 m is 0.32%.
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On what slope a 3 m wide rectangular channel (n= 0.014) should be constructed so that critical flow will occur at a normal depth of 1.2 m?
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