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Rs. 720 was divided among A, B, C, D, E. The sum received by them was in ascending order and in arithmetic progression. E received Rs. 40 more than A. How much did B receive?
Correct answer is '134'. Can you explain this answer?
Most Upvoted Answer
Rs. 720 was divided among A, B, C, D, E. The sum received by them was...
Let A receive Rs. a and let the difference between each consecutive person be Rs. d.
Amount received by E = a + 4 d
According to question,
Amount received by E = Amount received by A + 40
a + 4d = a + 40
4d = 40
d = 10
Also,
Total amount = a + (a + d) + (a + 2d) + (a + 3d) + (a + 4d)
720 = 5a + 10d
720 = 5a + 100
a = 124
∴ Amount received by B = a + d = 124 + 10 = Rs.134.
Hence, the correct answer is Rs. 134.
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Community Answer
Rs. 720 was divided among A, B, C, D, E. The sum received by them was...
Given:
- The total amount is Rs. 720.
- The sum received by A, B, C, D, E is in ascending order and in arithmetic progression.
- E received Rs. 40 more than A.

To find:
- How much did B receive?

Solution:

Let's assume that A received x amount of money.

Since E received Rs. 40 more than A, E received (x + 40) amount of money.

The sum received by A, B, C, D, E is in ascending order. Let's assume that B received y amount of money.

- C receives (x + 2y) amount of money.
- D receives (x + 3y) amount of money.

The sum of the amounts received by A, B, C, D, E is equal to Rs. 720.

So, we can write the equation as:
x + (x + y) + (x + 2y) + (x + 3y) + (x + 40) = 720.

Simplifying the equation, we get:
5x + 6y + 40 = 720,
5x + 6y = 720 - 40,
5x + 6y = 680.

Since the sum received by A, B, C, D, E is in arithmetic progression, the difference between any two consecutive terms is the same.

So, the difference between B and A is y.

The difference between C and B is y.

The difference between D and C is y.

Hence, the common difference is y.

Now, let's find the values of x and y by substituting y = 1, 2, 3... and solving the equation 5x + 6y = 680.

When y = 1, x = 100.

When y = 2, x = 80.

When y = 3, x = 60.

When y = 4, x = 40.

When y = 5, x = 20.

When y = 6, x = 0.

The sum received by A, B, C, D, E should be positive, so we can ignore the values of x and y when y > 4.

Therefore, when y = 1, the value of x is 100.

So, A received Rs. 100 and B received Rs. (100 + 1) = 101.

Hence, B received Rs. 101.

The correct answer is 101.
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Rs. 720 was divided among A, B, C, D, E. The sum received by them was in ascending order and in arithmetic progression. E received Rs. 40 more than A. How much did B receive?Correct answer is '134'. Can you explain this answer?
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