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Shyam's house, his office and his gym are all equidistant from each other. the distance between any 2 of them is 4 km. shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office. the total distance walked by shyam is?
Most Upvoted Answer
Shyam's house, his office and his gym are all equidistant from each ot...
Given information:
- Shyam's house, office, and gym are all equidistant from each other.
- The distance between any two of them is 4 km.

To find:
The total distance walked by Shyam.

Approach:
To solve this problem, we can consider a diagram to visualize the scenario and then calculate the distances walked by Shyam.

Diagram:
Let's assume that Shyam's house is H, his office is O, and his gym is G. The distances between each of them are 4 km.

```
H G O
```

Calculating distances:
1. Shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.

- Shyam walks from G to a point directly east of O, which is indicated by the dashed line in the diagram.
- This distance is the same as the distance between G and O, which is 4 km.

2. Shyam reverses direction and walks till he reaches a point directly south of his office.

- Shyam walks from the point directly east of O to a point directly south of O, which is indicated by the dotted line in the diagram.
- This distance is the same as the distance between the point directly east of O and the point directly south of O, which is also 4 km.

Total distance walked:
The total distance walked by Shyam is the sum of the distances calculated in steps 1 and 2.

Total distance walked = Distance walked from G to the point directly east of O + Distance walked from the point directly east of O to the point directly south of O

Total distance walked = 4 km + 4 km

Total distance walked = 8 km.

Therefore, Shyam walks a total distance of 8 km.
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Shyam's house, his office and his gym are all equidistant from each other. the distance between any 2 of them is 4 km. shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office. the total distance walked by shyam is?
Question Description
Shyam's house, his office and his gym are all equidistant from each other. the distance between any 2 of them is 4 km. shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office. the total distance walked by shyam is? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Shyam's house, his office and his gym are all equidistant from each other. the distance between any 2 of them is 4 km. shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office. the total distance walked by shyam is? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Shyam's house, his office and his gym are all equidistant from each other. the distance between any 2 of them is 4 km. shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office. the total distance walked by shyam is?.
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