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A classless address is given as 167.199.170.82/27. Find the first address.
  • a)
    167.199.170.32
  • b)
    167.199.170.82
  • c)
    167.199.170.64
  • d)
    167.199.170.78
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A classless address is given as 167.199.170.82/27. Find the first addr...
Given information:
Classless address = 167.199.170.82/27

To find: First address

Solution:
Step 1: Convert the subnet mask '/27' to its binary equivalent
11111111.11111111.11111111.11100000

Step 2: Apply the binary AND operation on the given IP address and the binary subnet mask to find the network address.
167.199.170.82 => 10100111.11000111.10101010.01010010
Subnet mask => 11111111.11111111.11111111.11100000
Network address => 10100111.11000111.10101010.01000000

Step 3: Convert the obtained network address from binary to decimal to find the first address.
10100111.11000111.10101010.01000000 => 167.199.170.64

Therefore, the first address for the given classless address is 167.199.170.64, which is option C.
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Community Answer
A classless address is given as 167.199.170.82/27. Find the first addr...
First address = (any address) AND (network mask).
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A classless address is given as 167.199.170.82/27. Find the first address.a)167.199.170.32b)167.199.170.82c)167.199.170.64d)167.199.170.78Correct answer is option 'C'. Can you explain this answer?
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