The work of 4 men is equal to the work of 6 women and the work of 9 w...
Given
The work of 4 men is equal to the work of 6 women and the work of 9 women is equal to the work of 12 boys.
8 men and 6 women working 8 hours a day complete work is 15 days.
Assumption:
Efficiency of a man = M unit work/hour.
Efficiency of a woman = W unit work/hour & efficiency of a boy = B unit work/hour.
Calculation:
⇒ 4M = 6W
⇒ 2M = 3W
The work of 9 women is equal to work of 12 boys.
⇒ 9W = 12B
⇒ 3W = 4B
∴ 2M = 3W = 4B
In 1 day, working 8 hours per day, total work done by 1 man = 8M
In 1 day, working 8 hours per day, total work done by 1 woman = 6W
8 men and 6 women working 8 hours a day complete a work is 15 days.
∴ Total work = (8M × 8 × 15) + (6W × 8 × 15) = 240 × (4M + 3W)
Assume that, in n days, 2 men, 3 women and 4 boys together working 6 hours daily will completer that work.
Total work done in this case = (2 × M × 6 × n) + (3 × W × 6 × n) + (4 × B × 6 × n)
In both cases total work will be equal.
⇒ (12M + 18W + 24B) × n = 240 × (4M + 3W)
⇒ 6 × (2M + 3W + 4B) × n = 240 × (4M + 3W)
⇒ (2M + 3W + 4B) × n = 40 × (4M + 3W)
⇒ (3W + 3W + 3W) × n = 40 × (6W + 3W)
⇒ n = 40
In 40 days 2 men, 3 women and 4 boys together working 6 hours daily will complete that work.
Hence, the correct option is (A).