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Read the following information carefully and answer the questions based on it.
There are two number series I and II given below have wrong numbers P and Q respectively.
I. 88, 186, 296, 422, 564, 722
II. 12, 29, 48, 69, 100, 131
Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.
K2–11K – (M2 + 8) = 0
- a)18
- b)14
- c)12
- d)9
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Read the following information carefully and answer the questions bas...
I. Number Series I: 88, 186, 296, 422, 564, 722
II. Number Series II: 12, 29, 48, 69, 100, 131
To find the wrong numbers P and Q, let's analyze both series individually.
I. Number Series I: 88, 186, 296, 422, 564, 722
To find the pattern in this series, let's look at the differences between consecutive terms:
98, 110, 126, 142, 158
The differences are increasing by 12 each time. Now, let's find the differences between these differences:
12, 16, 16, 16
The differences between differences are constant, indicating a quadratic pattern. The general formula for this series can be written as:
Series I (P) = an^2 + bn + c
To find the values of a, b, and c, we can substitute the given terms into the formula:
88 = a(1)^2 + b(1) + c
186 = a(2)^2 + b(2) + c
296 = a(3)^2 + b(3) + c
Solving these equations simultaneously, we can find the values of a, b, and c. However, since we only need to find the wrong number P, we can simply substitute the next term into the formula:
P = a(6)^2 + b(6) + c
II. Number Series II: 12, 29, 48, 69, 100, 131
To find the pattern in this series, let's look at the differences between consecutive terms:
17, 19, 21, 31, 31
The differences are not constant, indicating a non-linear pattern. Let's examine the differences between these differences:
2, 2, 10, 0
The differences between differences are also not constant. Therefore, it is difficult to determine the exact pattern in this series without more information.
However, we are given that the difference between P and Q is one of the roots of the equation:
K^2 – 11K – (M^2 + 8) = 0
We need to find the maximum value of M. To find that, we can use the quadratic formula:
K = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = -11, and c = -(M^2 + 8). The difference between P and Q is one of the roots, so we can substitute the difference into the equation:
K = (P - Q) = (-(-11) ± √((-11)^2 - 4(1)(-(M^2 + 8)))) / 2(1)
Simplifying the equation, we get:
K = (P - Q) = (11 ± √(121 + 4(M^2 + 8))) / 2
To maximize the value of M, we want to maximize the value inside the square root. Since the square root of a positive number is always positive, we need to maximize (M^2 + 8). The maximum value occurs when M is at its maximum value, which is when M = 0.
Substituting
II. Number Series II: 12, 29, 48, 69, 100, 131
To find the wrong numbers P and Q, let's analyze both series individually.
I. Number Series I: 88, 186, 296, 422, 564, 722
To find the pattern in this series, let's look at the differences between consecutive terms:
98, 110, 126, 142, 158
The differences are increasing by 12 each time. Now, let's find the differences between these differences:
12, 16, 16, 16
The differences between differences are constant, indicating a quadratic pattern. The general formula for this series can be written as:
Series I (P) = an^2 + bn + c
To find the values of a, b, and c, we can substitute the given terms into the formula:
88 = a(1)^2 + b(1) + c
186 = a(2)^2 + b(2) + c
296 = a(3)^2 + b(3) + c
Solving these equations simultaneously, we can find the values of a, b, and c. However, since we only need to find the wrong number P, we can simply substitute the next term into the formula:
P = a(6)^2 + b(6) + c
II. Number Series II: 12, 29, 48, 69, 100, 131
To find the pattern in this series, let's look at the differences between consecutive terms:
17, 19, 21, 31, 31
The differences are not constant, indicating a non-linear pattern. Let's examine the differences between these differences:
2, 2, 10, 0
The differences between differences are also not constant. Therefore, it is difficult to determine the exact pattern in this series without more information.
However, we are given that the difference between P and Q is one of the roots of the equation:
K^2 – 11K – (M^2 + 8) = 0
We need to find the maximum value of M. To find that, we can use the quadratic formula:
K = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = -11, and c = -(M^2 + 8). The difference between P and Q is one of the roots, so we can substitute the difference into the equation:
K = (P - Q) = (-(-11) ± √((-11)^2 - 4(1)(-(M^2 + 8)))) / 2(1)
Simplifying the equation, we get:
K = (P - Q) = (11 ± √(121 + 4(M^2 + 8))) / 2
To maximize the value of M, we want to maximize the value inside the square root. Since the square root of a positive number is always positive, we need to maximize (M^2 + 8). The maximum value occurs when M is at its maximum value, which is when M = 0.
Substituting
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Community Answer
Read the following information carefully and answer the questions bas...
According to question,
Root of given equation = (88 – 69) = 19
K2 – 11K – (M2 + 8) = 0
192 – 11 x 19 = (M2 + 8)
Value of M = 12, - 12
So maximum value of M = 12
Hence answer is option C
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Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer?
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Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer?.
Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Banking Exams.
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Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Read the following information carefully and answer the questions based on it.There are two number series I and II given below have wrong numbers P and Q respectively.I. 88, 186, 296, 422, 564, 722II. 12, 29, 48, 69, 100, 131Q. If difference between P and Q is one of the roots of the equation below, then find the maximum value of M.K2–11K – (M2 + 8) = 0a)18b)14c)12d)9e)None of theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Banking Exams tests.
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