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Given the following two statements:
S1: Every table with two single-valued attributes is in 1NF, 2NF, 3NF and BCNF.
S2: AB → C, D → E, E → C is a minimal cover for the set of functional dependencies AB → C, D → E, AB → E, E → C.
Which one of the following is CORRECT?
  • a)
    S1 is TRUE and S2 is FALSE
  • b)
    Both S1 and S2 are TRUE.
  • c)
    S1 is FALSE and S2 is TRUE
  • d)
    Both S1 and S2 are FALSE
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Given the following two statements:S1: Every table with two single-val...
Statement 1: TRUE
BCNF (Boyce Codd Normal Form):
A relation R is in BCNF whenever a non – trivial functional dependency X → A holds in R, where X is the super-key of R.
A binary relation is always in BCNF. A binary relation contains only two attributes.
Functional dependency that is possible from a binary relation is one.
Example:
Consider R(A, B), in this only one functional dependency is possible either A → B or B → A
In both the cases, left hand side will be the super key. In this way R(A, B) is always in BCNF.
If a relation is in BCNF then it is in 1NF, 2 NF and 3 NF
Statement 2: FALSE
Set 1 = {AB → C, D → E, AB → E, E→ C}
Set 2 = {AB → C, D → E, E → C}
Set 2 cannot derive   AB → E since in set 2 (AB)+ = {A, B, C}
The two sets of functional dependencies are not the same and hence one cannot be minimal of other.
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Community Answer
Given the following two statements:S1: Every table with two single-val...
Explanation:

S1: Every table with two single-valued attributes is in 1NF, 2NF, 3NF and BCNF
- This statement is FALSE.
- A table with two single-valued attributes may not necessarily be in 3NF or BCNF.
- For a table to be in 3NF, it should be in 1NF and 2NF first, and for a table to be in BCNF, it should be in 3NF.
- Therefore, S1 is incorrect.

S2: AB → C, D → E, E → C is a minimal cover for the set of functional dependencies AB → C, D → E, AB → E, E → C
- This statement is TRUE.
- A minimal cover for a set of functional dependencies is a set of dependencies that is both minimal and logically equivalent to the original set.
- In this case, the given set of functional dependencies AB → C, D → E, E → C can be simplified to AB → C, D → E, E → C.
- Therefore, S2 is correct.
Therefore, the correct answer is option 'A' where S1 is FALSE and S2 is TRUE.
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Given the following two statements:S1: Every table with two single-valued attributes is in 1NF, 2NF, 3NF and BCNF.S2: AB → C, D → E, E → C is a minimal cover for the set of functional dependencies AB → C, D → E, AB → E, E → C.Which one of the following is CORRECT?a)S1 is TRUE and S2 is FALSEb)Both S1 and S2 are TRUE.c)S1 is FALSE and S2 is TRUEd)Both S1 and S2 are FALSECorrect answer is option 'A'. Can you explain this answer?
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