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The approximate value of a root of x3 – 13 = 0, then 3.5 as initial value, after one iteration using Newton-Raphson method, isa)2.687b)2.678c)3.607d)3.597Correct answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The approximate value of a root of x3 – 13 = 0, then 3.5 as initial value, after one iteration using Newton-Raphson method, isa)2.687b)2.678c)3.607d)3.597Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The approximate value of a root of x3 – 13 = 0, then 3.5 as initial value, after one iteration using Newton-Raphson method, isa)2.687b)2.678c)3.607d)3.597Correct answer is option 'A'. Can you explain this answer?.

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