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In a rectangle PQRS, QS = 12 cm. ST is perpendicular to PR and TR = 8 cm. What is the area of the rectangle PQRS?
​(d) 54√2
  • a)
    48
  • b)
    96
  • c)
    48√2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a rectangle PQRS, QS = 12 cm. ST is perpendicular to PR and TR = 8...
PR = QS = 12. Therefore PT = PR - TR = 4
PS2 = PT2 + ST2 = PT2 + SM2 - TM2 = 16 + 36 - 4 = 48
PQ2 = QS2 - SP2 = 122 - 48 = 96
Area of the rectangle = PQ*PS = 48√2 ​
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