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Determine the value of a2 for the recurrence relation an = 17an-1 + 30n with a0 = 3.
- a)4387
- b)5484
- c)238
- d)1437
Correct answer is option 'D'. Can you explain this answer?
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Determine the value of a2 for the recurrence relation an= 17an-1+ 30n ...
Recurrence relation is given as:
an = 17an-1 + 30n
a0 = 3
To find a2, we need to substitute n=1 and n=2 in the given relation.
a1 = 17a0 + 30(1) = 17(3) + 30 = 81
a2 = 17a1 + 30(2) = 17(81) + 60 = 1437
Therefore, the value of a2 is 1437.
an = 17an-1 + 30n
a0 = 3
To find a2, we need to substitute n=1 and n=2 in the given relation.
a1 = 17a0 + 30(1) = 17(3) + 30 = 81
a2 = 17a1 + 30(2) = 17(81) + 60 = 1437
Therefore, the value of a2 is 1437.
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Determine the value of a2 for the recurrence relation an= 17an-1+ 30n ...
When n= 1, a1 = 17a0 + 30, Now a2 = 17a1 + 30*2. By substitution, we get a2 = 17(17a0 + 30) + 60. Then regrouping the terms, we get a2 = 1437, where a0 = 3.
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