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A star connected network consumes a power of 20 kW with a power factor of 0.8. Calculate the value of resistance of each coil when a supply voltage of 230 volts and 50 Hz is supplied between two phases of the network.
  • a)
    8 ohms
  • b)
    1.23 ohms
  • c)
    1 ohm
  • d)
    1.692 ohms
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A star connected network consumes a power of 20 kW with a power factor...
active power (P) = 20 kW
Vph = 230 V
VL = 230√3 V
power factor (cosϕ ) =  0.8.
cosϕ = P/S
S = P\cosϕ = 20/0.8 = 25 KVA
Then;
Also
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Community Answer
A star connected network consumes a power of 20 kW with a power factor...
To calculate the value of resistance (R) of each coil in a star connected network, we can use the following formula:

R = V / (I * √3 * PF)

Where:
R = resistance of each coil
V = supply voltage (230 volts)
I = current (given by P / (V * PF))
√3 = square root of 3
PF = power factor (0.8)

Let's calculate the current first:

P = power consumed by the network (20 kW)
V = supply voltage (230 volts)
PF = power factor (0.8)

I = P / (V * PF)
I = 20,000 / (230 * 0.8)
I ≈ 108.7 amps

Now, let's calculate the resistance:

R = V / (I * √3 * PF)
R = 230 / (108.7 * √3 * 0.8)
R ≈ 1.692 ohms

Therefore, the value of resistance for each coil in the star connected network is approximately 1.692 ohms.
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A star connected network consumes a power of 20 kW with a power factor of 0.8. Calculate the value of resistance of each coil when a supply voltage of 230 volts and 50 Hz is supplied between two phases of the network.a)8 ohmsb)1.23 ohmsc)1 ohmd)1.692 ohmsCorrect answer is option 'D'. Can you explain this answer?
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