In how many different ways can the letters of the word FIGHT be arranged?a)110b)120c)105d)115Correct answer is option 'B'. Can you explain this answer?

Question

Answer

Given
Total alphabets in word 'FIGHT' = 5
Concept Used
Total number ways of arrangement = n!
Calculation
The number of different ways of arrangement of n different words (without repetition) = 5!
⇒ 5 × 4 × 3 × 2 × 1 = 120
∴ The required answer is 120

Answer

Arranging the letters of the word FIGHT:

To find the number of different ways the letters of the word FIGHT can be arranged, we can use the concept of permutations. A permutation is an arrangement of objects in a specific order.

Total number of letters:
The word FIGHT has 5 letters.

Arranging the letters:
To arrange the letters of the word FIGHT, we need to consider that each letter is unique. Therefore, we can use the formula for permutations of distinct objects:

$\text{Number of arrangements} = n!$

Where n is the total number of objects.

In this case, n = 5 (since there are 5 letters in the word FIGHT).

So, the number of arrangements of the letters of the word FIGHT is:

$5! = 5 \times 4 \times 3 \times 2 \times 1 = 120$

Answer:
Therefore, the correct answer is option 'B', 120.

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