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Which of the following about SF4, SOF4 and COF2 molecules is correct?
  • a)
     
    Equatorial FSF bond angle in SOF4 will be less than in SF4 molecule
  • b)
    Hybridization state of sulphur in SF4 and SOF4 molecule will be different
  • c)
    The bond angle FCO will be less than 120° in molecule COF2
  • d)
    The axial FSF bond angle in SF4 is 180°
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Which of the following about SF4, SOF4and COF2molecules is correct?a)E...
Understanding COF2 and its Bond Angles
The correct answer to the question is option 'C', which states that the bond angle FCO in the molecule COF2 will be less than 120°. Here’s a detailed explanation of why this is true:

Hybridization and Molecular Geometry
- COF2 has a central carbon atom bonded to two fluorine atoms and one oxygen atom.
- Carbon in COF2 undergoes **sp² hybridization**, leading to a trigonal planar arrangement.

Effect of Lone Pairs on Bond Angles
- The oxygen atom has lone pairs, which cause **repulsion**. In COF2, the presence of the lone pair on oxygen leads to a distortion in the bond angles.
- While ideal trigonal planar bond angles are 120°, the lone pair compresses the FCO bond angle, making it less than 120°.

Comparing with SF4 and SOF4
- In SF4, the **axial FSF bond angle** is indeed 180°, but this is not the focus of the question.
- For SOF4, the **equatorial FSF bond angle** will be influenced by the presence of the oxygen atom and the lone pairs, resulting in different angles compared to SF4.

Conclusion
- Thus, the statement regarding the FCO bond angle being less than 120° in COF2 correctly reflects the impact of lone pairs on molecular geometry.
This understanding is crucial for JEE aspirants as it highlights how molecular geometry influences bond angles, especially in molecules with multiple atoms and lone pairs.
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Community Answer
Which of the following about SF4, SOF4and COF2molecules is correct?a)E...
Equatorial FSF bond angle is less in SFthan in SOF4 since lone pair repulsion is more than two electron pairs in double bond
In both SF4 and SOF4 the hybridisation state of S is same sp3d
The OCF bond angle on COF2 is more than 120° since two electron pairs in double bond repel more than one electron pair in C-F bonds.
Due to repulsion by lone pair the axial FSF bond angle is less than 180°
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Which of the following about SF4, SOF4and COF2molecules is correct?a)Equatorial FSF bond angle in SOF4will be less than in SF4moleculeb)Hybridization state of sulphur in SF4and SOF4molecule will be differentc)The bond angle FCO will be less than 120° in molecule COF2d)The axial FSF bond angle in SF4is 180°Correct answer is option 'C'. Can you explain this answer?
Question Description
Which of the following about SF4, SOF4and COF2molecules is correct?a)Equatorial FSF bond angle in SOF4will be less than in SF4moleculeb)Hybridization state of sulphur in SF4and SOF4molecule will be differentc)The bond angle FCO will be less than 120° in molecule COF2d)The axial FSF bond angle in SF4is 180°Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following about SF4, SOF4and COF2molecules is correct?a)Equatorial FSF bond angle in SOF4will be less than in SF4moleculeb)Hybridization state of sulphur in SF4and SOF4molecule will be differentc)The bond angle FCO will be less than 120° in molecule COF2d)The axial FSF bond angle in SF4is 180°Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following about SF4, SOF4and COF2molecules is correct?a)Equatorial FSF bond angle in SOF4will be less than in SF4moleculeb)Hybridization state of sulphur in SF4and SOF4molecule will be differentc)The bond angle FCO will be less than 120° in molecule COF2d)The axial FSF bond angle in SF4is 180°Correct answer is option 'C'. Can you explain this answer?.
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