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An eight-bit binary ripple UP counter with a modulus of 256 is holding the count 01111111. What will be the count after 135 clock pulses?
- a)0000 0101
- b)1111 1001
- c)0000 0110
- d)0000 0111
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
An eight-bit binary ripple UP counter with a modulus of 256 is holding...
Given information:
- An eight-bit binary ripple UP counter with a modulus of 256 is holding the count 01111111.
- We need to determine the count after 135 clock pulses.
Understanding a binary ripple UP counter:
- A binary ripple UP counter is a sequential circuit that increments its count value by 1 at each clock pulse.
- The count value is represented in binary form, which means it consists of multiple bits.
- In an eight-bit binary ripple UP counter, the count value ranges from 00000000 to 11111111, which is 0 to 255 in decimal.
Approach:
- We need to determine the count after 135 clock pulses, starting from the current count of 01111111.
- Since the modulus of the counter is 256, we can ignore any count values beyond 255 and consider them as overflow.
- We will simulate the counter operation for 135 clock pulses and observe the count after each pulse.
Simulation:
1. Starting count: 01111111 (127 in decimal)
2. Clock pulse 1: Increment count by 1
- New count: 10000000 (128 in decimal)
3. Clock pulse 2: Increment count by 1
- New count: 10000001 (129 in decimal)
4. Clock pulse 3: Increment count by 1
- New count: 10000010 (130 in decimal)
...
5. Clock pulse 128: Increment count by 1
- New count: 11111111 (255 in decimal)
6. Clock pulse 129: Increment count by 1
- New count: 00000000 (256 in decimal) - Overflow, reset to 00000000
7. Clock pulse 130: Increment count by 1
- New count: 00000001 (1 in decimal)
8. Clock pulse 131: Increment count by 1
- New count: 00000010 (2 in decimal)
...
9. Clock pulse 135: Increment count by 1
- New count: 00000110 (6 in decimal)
Answer:
- After 135 clock pulses, starting from the count 01111111, the new count will be 00000110 in binary or 6 in decimal.
- Therefore, the correct answer is option 'C' (0000 0110).
- An eight-bit binary ripple UP counter with a modulus of 256 is holding the count 01111111.
- We need to determine the count after 135 clock pulses.
Understanding a binary ripple UP counter:
- A binary ripple UP counter is a sequential circuit that increments its count value by 1 at each clock pulse.
- The count value is represented in binary form, which means it consists of multiple bits.
- In an eight-bit binary ripple UP counter, the count value ranges from 00000000 to 11111111, which is 0 to 255 in decimal.
Approach:
- We need to determine the count after 135 clock pulses, starting from the current count of 01111111.
- Since the modulus of the counter is 256, we can ignore any count values beyond 255 and consider them as overflow.
- We will simulate the counter operation for 135 clock pulses and observe the count after each pulse.
Simulation:
1. Starting count: 01111111 (127 in decimal)
2. Clock pulse 1: Increment count by 1
- New count: 10000000 (128 in decimal)
3. Clock pulse 2: Increment count by 1
- New count: 10000001 (129 in decimal)
4. Clock pulse 3: Increment count by 1
- New count: 10000010 (130 in decimal)
...
5. Clock pulse 128: Increment count by 1
- New count: 11111111 (255 in decimal)
6. Clock pulse 129: Increment count by 1
- New count: 00000000 (256 in decimal) - Overflow, reset to 00000000
7. Clock pulse 130: Increment count by 1
- New count: 00000001 (1 in decimal)
8. Clock pulse 131: Increment count by 1
- New count: 00000010 (2 in decimal)
...
9. Clock pulse 135: Increment count by 1
- New count: 00000110 (6 in decimal)
Answer:
- After 135 clock pulses, starting from the count 01111111, the new count will be 00000110 in binary or 6 in decimal.
- Therefore, the correct answer is option 'C' (0000 0110).
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Community Answer
An eight-bit binary ripple UP counter with a modulus of 256 is holding...
01111111 → 127
After 135 clock cycles, we will get
127 + 135 = 262
∴ The total number of clock pulses will be 262
As the modulus is 256,
After 256 clock pulses, the sequence will repeat.
262 = 256 + 6
∴ 00 00 00 00
257 → 00 00 00 01
258 → 00 00 00 10
259 → 00 00 00 11
260 → 00 00 01 00
261 → 00 00 01 01
262 → 00 00 01 10
After 135 clock cycles, we will get
127 + 135 = 262
∴ The total number of clock pulses will be 262
As the modulus is 256,
After 256 clock pulses, the sequence will repeat.
262 = 256 + 6
∴ 00 00 00 00
257 → 00 00 00 01
258 → 00 00 00 10
259 → 00 00 00 11
260 → 00 00 01 00
261 → 00 00 01 01
262 → 00 00 01 10
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An eight-bit binary ripple UP counter with a modulus of 256 is holding the count 01111111. What will be the count after 135 clock pulses?a)0000 0101b)1111 1001c)0000 0110d)0000 0111Correct answer is option 'C'. Can you explain this answer?
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Solutions for An eight-bit binary ripple UP counter with a modulus of 256 is holding the count 01111111. What will be the count after 135 clock pulses?a)0000 0101b)1111 1001c)0000 0110d)0000 0111Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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