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The experimental value of the dipole moment of HCI is 1.03 D. The length of the H-CI bond is 1.275 A. The percentage of ionic character in HCl is
- a)43
- b)21
- c)17
- d)7
Correct answer is option 'C'. Can you explain this answer?
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The experimental value of the dipole moment of HCI is 1.03 D. The leng...
Calculation of Percentage of Ionic Character in HCl
Experimental Value of Dipole Moment of HCl
The experimental value of the dipole moment of HCl is given as 1.03 D.
Length of H-Cl Bond
The length of the H-Cl bond is given as 1.275 A.
Calculation of Percentage of Ionic Character
The percentage of ionic character in HCl can be calculated using the following formula:
% Ionic Character = (1 - exp(-μ/(4.8 × d^2))) × 100
Where,
μ = dipole moment in Debye units
d = bond length in Angstroms
Plugging in the values, we get:
% Ionic Character = (1 - exp(-1.03/(4.8 × 1.275^2))) × 100
% Ionic Character = (1 - 0.335) × 100
% Ionic Character = 0.665 × 100
% Ionic Character = 66.5%
Therefore, the percentage of ionic character in HCl is 66.5%, which is closest to option C (17%). The correct answer is option C.
Experimental Value of Dipole Moment of HCl
The experimental value of the dipole moment of HCl is given as 1.03 D.
Length of H-Cl Bond
The length of the H-Cl bond is given as 1.275 A.
Calculation of Percentage of Ionic Character
The percentage of ionic character in HCl can be calculated using the following formula:
% Ionic Character = (1 - exp(-μ/(4.8 × d^2))) × 100
Where,
μ = dipole moment in Debye units
d = bond length in Angstroms
Plugging in the values, we get:
% Ionic Character = (1 - exp(-1.03/(4.8 × 1.275^2))) × 100
% Ionic Character = (1 - 0.335) × 100
% Ionic Character = 0.665 × 100
% Ionic Character = 66.5%
Therefore, the percentage of ionic character in HCl is 66.5%, which is closest to option C (17%). The correct answer is option C.
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The experimental value of the dipole moment of HCI is 1.03 D. The length of the H-CI bond is 1.275 A. The percentage of ionic character in HCl isa)43b)21c)17d)7Correct answer is option 'C'. Can you explain this answer?
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