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You are given two stacks with the element 1,2,3,4,5, which must be placed in the same sequence in both stacks. Once an element is added to a stack, it can only be popped and displayed (but it cannot be pushed onto the other stack again). So the possible actions are s.pop(), s.push(), and s.top() (to return the stack's top element), and the method display(int) outputs an integer result. Both stacks have access to these three operations. If it is not empty, you can do a pop operation whenever you want. Which of the following sequences cannot be produced with the aforementioned constraints?
  • a)
    3 1 2 4 5
  • b)
    4 1 5 2 3
  • c)
    4 2 1 3 5
  • d)
    5 4 3 2 1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
You are given two stacks with the element 1,2,3,4,5, which must be pla...
Let S1 and S2 be two stacks and let pop(), push (), and top() be the operations on the stack.
The element 1,2,3,4,5 in order.
Option 1:
To obtain 3 1 2 4 5
S1.push(1) ;
S2.push(2);
S1.push(3);
display(S1.top());
S1.pop();
display(S1.top())
S1.pop();
display(S2.top())
S2.pop();
S1.push(4)
display(S1.top())
S1.pop();
S1.push(5);
display(S1.top())
S1.pop();
Option 2 : 4 1 5 2 3
There can be no way to generate option 2.
Option 3:
To generate  4 2 1 3 5
S1.push(1);
S1.push(2);
S2.push(3);
S2.push(4);
display(S2.top());
S2.pop();
display(S1.top());
S1.pop();
display(S1.top());
S1.pop();
display(S2.top());
S2.pop();
S1.push(5);
display(S1.top());
S1.pop();
Option 4:
To obtain option 5 4 3 2 1.
Push all elements onto the  stacks, The stack will be like:
1 2 3 4 5, where 5 is present at the top of the stack and 1 is at the bottom of the stack. Now popping those elements and printing will output the sequence 5 4 3 2 1.
Hence the correct answer is 4 1 5 2 3.
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You are given two stacks with the element 1,2,3,4,5, which must be placed in the same sequence in both stacks. Once an element is added to a stack, it can only be popped and displayed (but it cannot be pushed onto the other stack again). So the possible actions are s.pop(), s.push(), and s.top() (to return the stacks top element), and the method display(int) outputs an integer result. Both stacks have access to these three operations. If it is not empty, you can do a pop operation whenever you want. Which of the following sequences cannot be produced with the aforementioned constraints?a)3 1 2 4 5b)4 1 5 2 3c)4 2 1 3 5d)5 4 3 2 1Correct answer is option 'B'. Can you explain this answer?
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